Procedure:
1) Integrate the function, from t =0 to t = 60 minutues to obtain the number of liters pumped out in the entire interval, and
2) Substract the result from the initial content of the tank (1000 liters).
Hands on:
Integral of (6 - 6e^-0.13t) dt ]from t =0 to t = 60 min =
= 6t + 6 e^-0.13t / 0.13 = 6t + 46.1538 e^-0.13t ] from t =0 to t = 60 min =
6*60 + 46.1538 e^(-0.13*60) - 0 - 46.1538 = 360 + 0.01891 - 46.1538 = 313.865 liters
2) 1000 liters - 313.865 liters = 613.135 liters
Answer: 613.135 liters
Answer:
46
Step-by-step explanation:
Its adding 12 each time
5-3/-4-2=-2/6 the slope of the line is -2/6. This is the case because you do y1-y2 over x1-x2. ANSWER -2/6
Answer:
960
Step-by-step explanation:
x = 0.6x + 384
Subtract 0.6x from both sides.
0.4x = 384
Divide both sides by 0.4
x = 960