Please help me it’s sixth grade math

The graph shows the height of a hiker above sea level.

dimaraw [331]

The correct answer is:

B) The variables are height and time. For the first part of the graph, the height is increasing slowly, which means the hiker is walking up a gentle slope. Flat parts of the graph show where the elevation does not change, which means the trail is flat here. The steep part at the end of the graph shows that the hiker is descending a steep incline.

Explanation:

The variables are marked on the graph. Time is marked along the x-axis, which means it is the independent variable. Height is marked along the y-axis, which means it is the dependent variable.

The first part of the graph rises slowly. This means the elevation does not change much over the time; this would be consistent with a gentle slope being climbed.

The flat areas are where the elevation does not change. This would be consistent with the hiker resting.

The steep decrease at the end shows that the elevation goes down quickly. This is consistent with the hiker climbing down a steep slope.

3 0

3 years ago

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Find a compact form for generating functions of the sequence 1, 8,27,... , k^3

pantera1 [17]

This sequence has generating function

$F(x)=\displaystyle\sum_{k\ge0}k^3x^k$

(if we include $k=0$ for a moment)

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k$

Take the derivative to get

$\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k$

$\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k$

Take the derivative again:

$\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k$

$\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k$

Take the derivative one more time:

$\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k$

$\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k$

so we have

$\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}$

5 0

3 years ago

Jaime hiked for 3 days across an island. He started at the shoreline, which is at an elevation of O feet.

Gre4nikov [31]

Answer:

D. 4120 feet

Step-by-step explanation:

Jamie lost on the third day:

2150 + 1970 = 4120 feet

Correct option is D.

4 0

3 years ago

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PLZZZ ANSWER :(-!!!!!! | | | v

elixir [45]

Answer: 1400

Step-by-step explanation: you add 40 and 30 then you times it by 20 because it said " what is the area of the part that's painted blue" it's trying to throw you off by having the other numbers by the window and the door.

8 0

3 years ago

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Someone plzzzz help me):

sergiy2304 [10]

C. x³-4x²-16x+24.

In order to solve this problem we have to use the product of the polynomials where each monomial of the first polynomial is multiplied by all the monomials that form the second polynomial. Afterwards, the similar monomials are added or subtracted.

Multiply the polynomials (x-6)(x²+2x-4)

Multiply eac monomial of the first polynomial by all the monimials of the second polynomial:

(x)(x²)+x(2x)-(x)(4) - (6)(x²) - (6)(2x) - (6)(-4)

x³+2x²-4x -6x²-12x+24

Ordering the similar monomials:

x³+(2x²-6x²)+(-4x - 12x)+24

Getting as result:

x³-4x²-16x+24

3 0

3 years ago