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Wewaii [24]
2 years ago
11

Logan earns $35,000. He pays 6% income tax. How much does he pay for income tax?

Mathematics
2 answers:
garik1379 [7]2 years ago
8 0
Logan pays atleast $2,100
svetoff [14.1K]2 years ago
5 0

Answer: 2100$

Step-by-step explanation:

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Gavin’s unpaid credit card balance is $2103.23. His APR is 14.4%.
insens350 [35]

Answer:

b

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3 years ago
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4.6 x 10^3 in standard form
serg [7]

Answer:

4600

Step-by-step explanation:

Standard Form: 4.6

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Its not very clear but if someone could help me with the answers that would be great
Pie
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2 years ago
Which interval contains a local minimum for the graphed function?
DochEvi [55]

Answer : Option D is correct i.e [2.5,4]

Explanation :

Suppose our function is f(x)

then the value of f(x) is minimum where

it reaches -0.44 and 3 with two different intervals .

As we know that for finding the local minimum ,

the criteria is that  f'(x)=0 .

So, here

f'(-0.44)=0 and

f'(3)=0

both are the local minimum point for the function f(x)

but -0.44 is the global minimum point .

In our case for [2.5,4] is the required interval where f(x) reaches its  local minimum.

4 0
3 years ago
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Solve the following equation. X cubed minus 6X squared plus 6X equals zero
anyanavicka [17]

We have to solve this equation:

x^3-6x^2+6x=0

Third degree polynomials like this one are not easily solved, but this one has a root at x = 0. The let us factorize this polynomial as x times a second degree polynomial:

\begin{gathered} x^3-6x^2+6x=0 \\ x(x^2-6x+6)=0 \end{gathered}

Now we can find the roots of the quadratic polynomial as:

\begin{gathered} x=\frac{-(-6)\pm\sqrt[]{(-6)^2-4\cdot1\cdot6}}{2\cdot1} \\ x=\frac{6\pm\sqrt[]{36-24}}{2} \\ x=\frac{6\pm\sqrt[]{12}}{2} \\ x=\frac{6\pm\sqrt[]{4\cdot3}}{2} \\ x=\frac{6\pm2\sqrt[]{3}}{2} \\ x=3\pm\sqrt[]{3} \\ x_1=3-\sqrt[]{3} \\ x_2=3+\sqrt[]{3} \end{gathered}

Then, the solutions to the equation are:

x = 0

x = 3 - √3

x = 3 + √3

4 0
1 year ago
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