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Scrat [10]
2 years ago
6

Solve the inequality. Graph your solution. a + 5 >-8

Mathematics
1 answer:
enyata [817]2 years ago
3 0

Answer:

a > -13

Step-by-step explanation:

a + 5 > -8

a > -8 - 5

a > -13

__(___________________ +∞   or (-13 , +∞ )

  -13   -12   -11   -10       .............+∞                        

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5 0
3 years ago
R = -5, s = 2, t = 7, u = -1 <br><br><br> 5r - 4
Doss [256]
5r-4 and r=-5 so it would be 5(-5)=-20, then -4 , so is is -24
8 0
2 years ago
Niech ktoś pomoże !<br> a)5 2\7 +1 3\7 -1\7=<br> b)4 5\9 -2 4\9 +3 2\9=<br> c)2 2\3 -(1 4\9 +2 3\9=
kvv77 [185]

A) 6 4/7

B) 5 3/9

C) 6 6/3

5 0
3 years ago
4- What are the different waysto solve a quadratic? List examples of each
TiliK225 [7]
I know of two ways to solve quadratic equations. The first is through factoring. Let us take the example (x^2)+2x+1=0. We can factor this equation out and the factors would be (x+1)(x+1)=0. To solve for the roots, we equate each factor to 0, that is

x+1=0; x+1=0

In this case, the factors are the same so the root of the equation is

x=1.

The other way is to use the quadratic formula. The quadratic formula is given as [-b(+-)sqrt(b^2-4ac)]/2a where, using our sample equation above, a=1, b=2 and c=1. Substitute these to the formula, and you will get the same answer as the method above.
8 0
3 years ago
Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if:a) a
lara31 [8.8K]

Answer:

A) 0.0009765625

B) 0.0060466176

C) 2.7756 x 10^(-17)

Step-by-step explanation:

A) This problem follows a binomial distribution. The number of successes among a fixed number of trials is; n = 10

If a 0 bit and 1 bit are equally likely, then the probability to select in 1 bit is; p = 1/2 = 0.5

Now the definition of binomial probability is given by;

P(K = x) = C(n, k)•p^(k)•(1 - p)^(n - k)

Now, we want the definition of this probability at k = 10.

Thus;

P(x = 10) = C(10,10)•0.5^(10)•(1 - 0.5)^(10 - 10)

P(x = 10) = 0.0009765625

B) here we are given that p = 0.6 while n remains 10 and k = 10

Thus;

P(x = 10) = C(10,10)•0.6^(10)•(1 - 0.6)^(10 - 10)

P(x=10) = 0.0060466176

C) we are given that;

P((x_i) = 1) = 1/(2^(i))

Where i = 1,2,3.....,n

Now, the probability for the different bits is independent, so we can use multiplication rule for independent events which gives;

P(x = 10) = P((x_1) = 1)•P((x_2) = 1)•P((x_3) = 1)••P((x_4) = 1)•P((x_5) = 1)•P((x_6) = 1)•P((x_7) = 1)•P((x_8) = 1)•P((x_9) = 1)•P((x_10) = 1)

This gives;

P(x = 10) = [1/(2^(1))]•[1/(2^(2))]•[1/(2^(3))]•[1/(2^(4))]....•[1/(2^(10))]

This gives;

P(x = 10) = [1/(2^(55))]

P(x = 10) = 2.7756 x 10^(-17)

3 0
3 years ago
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