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3 years ago

Solve the inequality. Graph your solution. a + 5 >-8

Mathematics

1 answer:

enyata [817]3 years ago

3 0

Answer:

a > -13

Step-by-step explanation:

a + 5 > -8

a > -8 - 5

a > -13

__(___________________ +∞ or (-13 , +∞ )

-13 -12 -11 -10 .............+∞

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I need help to the attachment down below, first answer gets 5 stars and a thanks!

Gekata [30.6K]

Answer:

base = 15 units

Step-by-step explanation:

We are given area of a triangle = 52.5 sq. units

Height is given as 7 and we have to find the base.

Using formula for area of triangle:

Area of triangle = $\frac{base*height}{2}$

$52.5 = \frac{base*height}{2}$

$52.5 = \frac{base*7}{2}$

52.5 * 2 = base × 7

105 = base × 7

base = 15

3 0

3 years ago

Read 2 more answers

there are 3 slices of pie left, and the angle measurement is 72 degrees, how many slices was the pie cut in to

Daniel [21]

15; this is because 3 pies make up 72
with this you can make it so that 3x=72
After this you need to find x which is a single pie
so; (3x/3)=(72/3)
x= 24
Since you know a circle is 360 degrees all around the center
You can do 360/24 making it 15 pies.

7 0

3 years ago

Find the measure of Angle 3. measure of angle 1 = x measure of angle 2 = x-6

ipn [44]

Part A: What is the mean of the data? Show your work. (4 points)

Part B: Use your answer from Part A to calculate the mean absolute deviation for the data. Show your work. (6 points)

5 0

3 years ago

Find all the zeros of the polynomial function p(x) = x3 – 5x2 + 33x – 29

hram777 [196]

Answer:

$\large \boxed{\sf \ \ x=1, \ \ x=2+5i, \ \ x=2-5i \ \ }$

Step-by-step explanation:

Hello,

I assume that we are working in $\mathbb{C}$ , otherwise there is only one zero which is 1. Please consider the following.

First of all, we can notice that 1 is a trivial solution as

$p(1) = 1^3-5\cdot 1^2 + 33\cdot 1-29=1-5+33-29=0$

It means that (x-1) is a factor of p(x) so we can find two real numbers, a and b, so that we can write the following.

$p(x)=(x-1)(x^2+ax+b)=x^3+ax^2+bx-x^2-ax-b=x^3+(a-1)x^2+(b-a)x-b$

Let's identify like terms as below.

a-1 = -5 <=> a = -5 + 1 = -4

b-a = 33

-b = -29 <=> b = 29

$\boxed{ \ p(x)=(x-1)(x^2-4x+29) \ }$

Now, we need to find the zeroes of the second factor, meaning finding x so that:

$x^2-4x+29=0 \ \text{ complete the square, 29 = 25 + 4} \\ \\ x^2-2\cdot 2 \cdot x+2^2+25=0 \\ \\ (x-2)^2=-25=(5i)^2 \ \text{ take the root } \\ \\x-2=\pm 5i \ \text{ add 2 } \\ \\ x = 2+5i \ \text{ or } \ x = 2-5i$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0

3 years ago

X+2(x+3(x+4(x+5)))=153

Allushta [10]

Answer:

$x=1$

Step-by-step explanation:

Here first open the inner parentheses and use the distributive property,

$4(x+5)=4x+20\\\\(x+4(x+5))=(x+4x+20)=(5x+20)\\\\3(x+4(x+5))=3(5x+20)=15x+60\\\\(x+3(x+4(x+5)))=(x+15x+60)=16x+60\\\\2(x+3(x+4(x+5)))=2(16x+60)=32x+120\\\\x+2(x+3(x+4(x+5)))=x+32x+120=33x+120\\\\\\Hence\ x+2(x+3(x+4(x+5)))=x+32x+120=33x+120\\\\\Rightarrow 33x+120=153\\\\33x=153-120\\\\33x=33\\\\x=1$

3 0

3 years ago