Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus
First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°.
Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.
For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.



Similarly, we have



Now, to find the lengths of the diagonals,


So, the lengths of the diagonals are 10 and 10√3.
Answer: 10 and 10√3 units
25x^2+10x+1
25x^2+5x+5x+1
5x(5x+1)+1(5x+1)
(5x+1)(5x+1)
(5x+1)^2
Answer:
a reflection across line bc
Step-by-step explanation:
maybe, I think so
Answer:
be careful,
brainly will ban your account
please use brainly if you want to ask a question that you need help on or you can help people
Step-by-step explanation:
Answer:
Answer in terms of π=144π m^3
Answer by replacing π with 3.14 is 452.16 approximately 452.2m^3
Answer to the nearest whole no. is 452m^3
Step-by-step explanation:


















