Can anyone help me expand this please?

Here!!!!!!!!!!!!!! For Kawaii cos 2007 (it needs more words lol.)

Naily [24]

AAAAAAAAAAAAAAAAAA AAAAAAAAAA A AAAAAAAAA AAAAAAAAAA AAAAAAAAAAA A A A AAAAAAA A A AAAAA AAAA.

Step-by-step explanation:

E

8 0

3 years ago

Read 2 more answers

Thе іmagе оf (-2, 5) is (1, 1).

dem82 [27]

Answer:

(6, -2)

Step-by-step explanation:

To get to x=1 from x=-2, you must add 3 to the x-coordinate. Only one answer choice has an x-coordinate that is 3 more than that of the given point:

3 + 3 = 6

The image point is (6, -2).

_____

Check

To get from a y-coordinate of 5 to an image point y-coordinate of 1, you must subtract 4. If you subtract 4 from the y-coordinate of (3, 2), you get 2-4 = -2, the y-coordinate in the chosen answer above.

8 0

3 years ago

The repeating decimal,0.27 repeting, is converted to the fraction 3/x. What is the value of x in the fraction?

Nuetrik [128]

Answer:5/18=.2777777777777

Step-by-step explanation:

.27777 (7 repeating)

100x=27.7777

10x= 2.7777

Subtract

90x=25

x=25/90=5/18

Check

5/18=.2777777777777

Hope that helps.

7 0

4 years ago

The measure of a square wall is 9 feet 7 inches on each side. Estimate the square feet a painter would have to cover to the near

Nookie1986 [14]

First, convert those inches to feet.
7in =ish 0.5833333
(you find this by dividing 7/12 on a calculator)
Now you just square 9.583333333
9.583333333^2
9.583333333 * 9.583333333
91.84027777ish
Rounded to the nearest foot, means the answer is 92ft.

5 0

3 years ago

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

3 years ago