<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>
Answer:
A. 57 7/9
Step-by-step explanation:
4 1/3 x 3 1/3 = 14 4/9
14 4/9 x 4 = 57 7/9
83-63=20
So your answer is 20
Answer:
Step-by-step explanation:
660
Volume for a cone is 1/3 pi * r^2*h, where r is radius and h is height. We have diameter = 1/2 radius. Thus, radius = 1.5in. We also have volume is 12 in. Using formula for volume of a cone and plugging in what we know, we have 12 = 1/3*pi*(1.5)^2*h, were solving for h. To get, h= (12*3)/(pi*(1.5)^2), which is approximately 5.0931in, 5 inches
