Length= 40cm
Breadth= 22cm
Perimeter of the rectangle= Length of the wire
=2(l+b)= 2(40cm + 22cm)
=2\times62cm = 124cm
Now, the wire is rebent into a square.
Perimeter= 124cm
4\times side=124
Therefore side= \frac{124}{4}cm= 31cm
So, the measure of each side= 31cm
Area of rectangular shape= l\times b
=40cm\times22cm
=880cm^2
Area of a square shape= \left(Side\right)^2
=\left(31\right)^2=961cm^2
Since 961cm^2\ >\ 880cm^2
Hence, the square encloses more area.
X^(16x^2-1) factor the expression
The answer to the graph
X^3(4x-1)(4x+1)
N can be 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 over or under the correct amount
16, because its 12 and you add one-third to 12 so that means its $16
The heat produced by current I is
H = I²R
where
R = resistance.
According to the formula, heat produced is proportional to the square of the current.
When a current of I = 2 amps is applied, the heat produced is
H = 10x³ + 80.
This heat includes heat due to a fixed current of 2 amps, and heat due to a variable current of x amps.
Because the heat produced is proportional to the square of the current, write the expressions as
H = (10x)*(x²) + 20*(2²)
The second term on the right is heat due to the fixed current of 2 amps, written as
20*(2²).
Therefore the fixed resistance is R = 20 ohms, and the square of the fixed current is 2².
The first term represents heat due to variable resistance, written as
(10x)*(x²).
Therefore the variable resistance is 10x, and the square of the variable current is x².
Answer:
The variable current is 10x.
