Complete question :
A right triangle has side lengths AC = 7 inches, BC = 24 inches, and AB = 25 inches.
What are the measures of the angles in triangle ABC?
a) m∠A ≈ 46.2°, m∠B ≈ 43.8°, m∠C ≈ 90°
b) m∠A ≈ 73.0°, m∠B ≈ 17.0°, m∠C ≈ 90°
c) m∠A ≈ 73.7°, m∠B ≈ 16.3°, m∠C ≈ 90°
d) m∠A ≈ 74.4°, m∠B ≈ 15.6°, m∠C ≈ 90°
Answer:
c) m∠A ≈ 73.7°, m∠B ≈ 16.3°, m∠C ≈ 90°
Step-by-step explanation:
Given:
Length AC = 7 inches
Length BC = 24 inches
Length AB = 25 inches
Since it is a right angle triangle,
m∠C = 90°
To find the measures of the angle in ∠A and ∠B, we have :
For ∠A:
∠A = 73.7°
For ∠B:
∠B = 16.26 ≈ 16.3°
Therefore,
m∠A = 73.7°
m∠B = 16.3°
m∠C = 90°
Answer:
659.4 cm^2
Step-by-step explanation:
The area of the curved surface of the cone = πrL
= π*7*16
= 3.14 * 112
= 351.68 cm^2,
Surface area of the hemisphere = 2 π r^2
= 2*3.14*7^2
= 307.72 cm^2.
Total area = 351.68 + 307.72
= 659.4 cm^2.
10.5, since 35 is between 30 and 40 ((30+40)/2), the mistakes that correspond with them are 9 and 12, the number in between them is 10.5 (9+12=21, 21/2 is 10.5)
(5.2,7.6)
mean=6.4
standard deviation=0.6
we have to find the range in which at least 75% of the data will reside
1-1/k²=0.75
1/k²=1-0.75
1/k²=0.25
k²=1/0.25=4
k=2
so, k=2
The range of values can be computed as mean±k(standard deviation).
Thus, the range in which at least 75% of the data will reside is
(mean-k(standard deviation), mean+ k(standard deviation))
(6.4-2(0.6),6.4+2(0.6)
(6.4-1.2,6.4+1.2)
(5.2,7.6)
learn more of standard deviation here brainly.com/question/14671301
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Answer:
Rs. 105 is divided into Rs. 60 and Rs. 45
Step-by-step explanation: