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Marianna [84]
3 years ago
10

Class A has 26 pupils and class B has 15 pupils.

Mathematics
2 answers:
Troyanec [42]3 years ago
8 0

Answer:

It's 49.4

Step-by-step explanation:

((26*33)+(15*x))/41=39

((858)+(15*x))/41=39 ‖*41

(858)+(15*x)=1599 ‖-858

15*x=741 ‖/15

x=49.4

lubasha [3.4K]3 years ago
4 0

Answer:

Concept: Real World Analysis

  1. So we know A has an average of 33
  2. We know A+B/2= 39
  3. Hence we will solve for b
  4. \frac{33 + x}{2}  = 39
  5. x = 45
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3 years ago
The height of a triangle is 5 cm shorter than its base. If the area of the triangle is 25 cm2, find the height of the triangle.
Olin [163]

Answer:

h = 5\ cm

Step-by-step explanation:

Let's call B at the base of the triangle and call h at the height of the triangle. Then we know that:

The height of a triangle is 5 cm shorter than its base. This means that:

h = B-5.

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By definition the area of a triangle is:

A = 0.5Bh

For this triangle we know that A = 25\ cm^2 and h = B-5. We substitute these values in the equation and solve for B.

25 = 0.5B (B-5)

0.5B ^ 2-\frac{5}{2}B-25 = 0

Now we use the quadratic formula to solve the equation.

For an equation of the form ax ^ 2 + bx + c = 0 the quadratic formula is:

B=\frac{-b\±\sqrt{b^2-4ac}}{2a}

In this case note that:  a=0.5,\ \ b=-\frac{5}{2}\ \ c=-25

Then:

B=\frac{-(-\frac{5}{2})\±\sqrt{(-\frac{5}{2})^2-4(0.5)(-25)}}{2(0.5)}

B=\frac{\frac{5}{2}\±\sqrt{\frac{25}{4}+50}}{1}

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The solutions are:

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6 0
3 years ago
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ANSWER

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Answer:

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