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3 years ago

Solve for x? A. 5 B.6/3 C.9 D.10

Mathematics

1 answer:

iragen [17]3 years ago

8 0

Answer:

Step-by-step explanation:

You're supposed to notice that the side 6 and x are the same sides of a similar triangle.. so then you can decide what 4 * ( y) = 6.... y =1.5 and then just multiply 6*y = ( your answer )

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topjm [15]

Im sorry i just wanna get points

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3 years ago

Which expression is equivalent to 4 square root<br> Of x^10

Airida [17]

A is the answer to this question

4 0

3 years ago

Graph the function f(x)=x^2+4x-12

poizon [28]

Use those coordinates (x,y) x negative left side of coodinate plane y negative down side of the coordinate plane positive x is right side and positive y is up

4 0

3 years ago

Find the missing side length. if necessary , round you’re answer to the nearest tenth ! pls help

Natalija [7]

Answer:

Step-by-step explanation:

1. Use the Pythagorean theorom: a^2+b^2=c^2.

C is the missing side here, which is the hypotenuse of the triangle. The other two sides and be put into the equation either way. Doesn't matter the order.

15^2 + 36^2 =c^2

2. Evaluate 15^2 and 36^2 and add the results.

15^2 = 225

36^2 = 1,296

225+1,296= 1,521

3. Take the square root of the answer.

√1521 = 39

6 0

3 years ago

Let , 4 ,− 7 be a point on the terminal side of θ . find the exact values of cos θ , csc θ , and tan θ .

Makovka662 [10]

Ok, you are given a point and you need to find the exact values for $cos \theta csc \theta & tan \theta$

First thing first. We need to see if we are working with a unit circle and find the radius.

How to tell if we are working with a unit circle?
We know $x^2 + y^2 = r^2$ is a circle.

We know that to find the radius we can use the following formula:
$r^2 = \sqrt{x^2 + y^2}$

If $r^2 = \sqrt{x^2 + y^2} = 1$ we are working with a unit circle.

Lets see if it = 1.
$r^2 = \sqrt{4^2 + -7^2}$
$r^2 = \sqrt{16 + 49}$
$r^2 = \sqrt{65}$

Square both sides now
$\sqrt{r^2} = \sqrt{\sqrt{65}}$
$r = \pm 65^{\frac{1}{4}}}$

Since we squared, we have a + and a - but we disregard the - because we do not have - radii
$r = 65^{\frac{1}{4}}}$
We can also say
$r = \sqrt[4]{65}$

Ok, since r does not equal 1, we are not working with a unit circle but we have found r, which is our radius.

Now that we know the value of r, which is $r = 65^{\frac{1}{4}}}$ , we need to look at the identities of cos, csc and tan.

The identities:
$cos \theta = \frac{x}{r}$
$csc \theta = \frac{1}{y}$
$tan \theta = \frac{y}{x}$

Now that we know their identities and know the radius of our circle, we can find the exact values of cos, csc and tan.

$cos \theta = \frac{x}{r} = \frac{4}{65^{\frac{1}{4}}}$
$csc \theta = \frac{1}{y} = \frac{1}{-7}$
$tan \theta = \frac{y}{x} = \frac{-7}{4}$

The exact values for cos, csc and tan given the point (4,-7) are:
$cos \theta = \frac{4}{65^{\frac{1}{4}}}$
$csc \theta = \frac{1}{-7}$
$tan \theta = \frac{-7}{4}$

4 0

3 years ago