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3 years ago

2. Draw the image of ∆RST under the dilation with scale factor ⅓ and center of dilation at the origin. Label the image ∆R’S’T’.

Mathematics

1 answer:

Alchen [17]3 years ago

6 0

Since center of dilation is the origin, this is easy. Just divide all of the x and y coordinate values by 3. Place the new point on the graph, and draw the triangle.

R' = R(3,6)/3 = (3/3,6/3)=(1,2). So R'(1,2)
S' = S(-3,6)/3 = (-3/3,6/3)=(-1,2). So S'(-1,2)
T' = T(-6,-6)/3 = (-6/3,-6/3)=(-2,-2). So T'(-2,-2)

So you now know the location of the 3 new points. R' at (1,2), S' at (-1,2) and T' at (-2,-2). Simply draw those 3 points on your graph and connect the lines to make a new triangle.

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7. A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the

svp [43]

Answer: 475.59 meters .

Step-by-step explanation:

The correct equation is the following:

$y =-0 .02x^2 +9.5x + 5.6$

For this exercise you need to use the Quadratic formula:

$x = \frac{-b\±\sqrt{b^2-4ac}}{2a}$

In this case you can identify that the values of "a", "b" and "c" are:

$a=-0.02\\\\b=9.5\\\\c=5.6$

Now you must substitute these values into the Quadratic formula and then evaluate. You get:

$x=\frac{-9.5\±\sqrt{(9.5)^2-4(-0.02)(5.6)}}{2(-0.02)}\\\\x_1=475.588\\x_2=-0.588$

Choose the positive one and round it to the nearest hundreth:

$x_1\approx 475.59$

4 0

3 years ago

A school district is considering moving the start of the school day at Groveland High from 8:00 a.m. to 9:00 a.m. to allow stude

DaniilM [7]

Answer:

The answer is " $\bold{(7.1-8.3) \pm 1.665 \sqrt{\frac{(1.7)^2}{50}+\frac{(1.9)^2}{39}} }\\\\$ "

Step-by-step explanation:

Given values:

$\bar{x_1}=7.1\\\\\bar{x_2}=8.3\\\\s_1=1.7\\\\s_2=1.9\\\\n_1=50\\\\n_2=39$

Using formula:

$\to (\bar{x_1} -\bar{x_2}) \pm t \sqrt{\frac{(s_1)^2}{n_1}+\frac{(s_1)^2}{n_2}} \\\\$

Put the values in the above formula:

$\to (7.1-8.3) \pm 1.665 \sqrt{\frac{(1.7)^2}{50}+\frac{(1.9)^2}{39}} \\\\$

4 0

3 years ago

Check all of the ordered pairs that satisfy the equation below.y=2/5x

zvonat [6]

We are going to do this step by step:

Let's start with option A

X = 25 and Y = 5/2

$y=\frac{2}{5}\cdot x=\frac{2}{5}\cdot25=\frac{2\cdot25}{5}=\frac{50}{5}=\frac{5\cdot10}{5\cdot1}=10$

In this case, when X = 25 , then Y = 10 ,which is different to 5/2

X = 14 , Y = 35

$y=\frac{2}{5}\cdot14=\frac{28}{5}$

In case, when X = 14, then Y = 28/5, which is different to 35

X = 40 , Y = 24

$y=\frac{2}{5}\cdot40=\frac{80}{5}=16$

Similarly, in this case, when X = 40, then Y = 16, which is different to 24

X = 10 , Y=4

$y=\frac{2}{5}\cdot10=\frac{20}{5}=4$

Now, in this case, we can see that when X = 10, then Y = 4 which is the same as the given value of Y

X = 50 , Y = 20

$y=\frac{2}{5}\cdot50=\frac{100}{5}=20$

In this case, the values of Y are also the same.

X = 30 , Y = 12

$y=\frac{2}{5}\cdot30=\frac{60}{5}=12$

Again, in this case, the values of Y are the same, so the pair satisfies the equation.

In conclusion: options D, E and F satisfy the equation

3 0

1 year ago

234/8 as a mixed number

uysha [10]

Calculate out how many times the denominator goes into the numerator. To do that, divide 234 by 8 and keep only what is to the left of the decimal point:

8 0

3 years ago

PLEASE ANSWER

Over [174]

Answer:

true

Step-by-step explanation:

8 0

3 years ago