All categories

2 years ago

Someone please help!!<3

Mathematics

1 answer:

Nataliya [291]2 years ago

4 0

Answer:

the answer is c

Step-by-step explanation:

the answer is c

You might be interested in

Kim paid

Anna11 [10]

Answer:

Sherri paid the most

Step-by-step explanation:

35% > 33%

3 0

3 years ago

Read 2 more answers

Esmerelda bought a bag of jelly beans. There were 24 green jelly beans, which made up 8%, percent of all the jelly beans in the

Margarita [4]

So, let's look at the problem once again.

8%, or 8/100 of the bag were green jelly beans.

Let's see what we can do to find out a number of other jelly beans, not including the green ones.

We know that 92% of jelly-beans are not green.

92% is 11.5 times more than 8%
(92/8)

24 (or 8%) times 11.5 = 276

276 - number of jelly beans that are not green.

276 plus 24 = 300.

Answer: 300 jelly beans were in one bag.

6 0

3 years ago

Can y’all hwelp mwe pweasee

Musya8 [376]

The only correct statements are the second one and the last one.

4 0

2 years ago

Write down the explicit solution for each of the following: a) x’=t–sin(t); x(0)=1

Kay [80]

Answer:

a) x=(t^2)/2+cos(t), b) x=2+3e^(-2t), c) x=(1/2)sin(2t)

Step-by-step explanation:

Let's solve by separating variables:

$x'=\frac{dx}{dt}$

a) x’=t–sin(t), x(0)=1

$dx=(t-sint)dt$

Apply integral both sides:

$\int {} \, dx=\int {(t-sint)} \, dt\\\\x=\frac{t^2}{2}+cost +k$

where k is a constant due to integration. With x(0)=1, substitute:

$1=0+cos0+k\\\\1=1+k\\k=0$

Finally:

$x=\frac{t^2}{2} +cos(t)$

b) x’+2x=4; x(0)=5

$dx=(4-2x)dt\\\\\frac{dx}{4-2x}=dt \\\\\int {\frac{dx}{4-2x}}= \int {dt}\\$

Completing the integral:

$-\frac{1}{2} \int{\frac{(-2)dx}{4-2x}}= \int {dt}$

Solving the operator:

$-\frac{1}{2}ln(4-2x)=t+k$

Using algebra, it becomes explicit:

$x=2+ke^{-2t}$

With x(0)=5, substitute:

$5=2+ke^{-2(0)}=2+k(1)\\\\k=3$

Finally:

$x=2+3e^{-2t}$

c) x’’+4x=0; x(0)=0; x’(0)=1

Let $x=e^{mt}$ be the solution for the equation, then:

$x'=me^{mt}\\x''=m^{2}e^{mt}$

Substituting these equations in c)

$m^{2}e^{mt}+4(e^{mt})=0\\\\m^{2}+4=0\\\\m^{2}=-4\\\\m=2i$

This becomes the solution m=α±βi where α=0 and β=2

$x=e^{\alpha t}[Asin\beta t+Bcos\beta t]\\\\x=e^{0}[Asin((2)t)+Bcos((2)t)]\\\\x=Asin((2)t)+Bcos((2)t)$

Where A and B are constants. With x(0)=0; x’(0)=1:

$x=Asin(2t)+Bcos(2t)\\\\x'=2Acos(2t)-2Bsin(2t)\\\\0=Asin(2(0))+Bcos(2(0))\\\\0=0+B(1)\\\\B=0\\\\1=2Acos(2(0))\\\\1=2A\\\\A=\frac{1}{2}$

Finally:

$x=\frac{1}{2} sin(2t)$

7 0

3 years ago

When I double my number add 4 and then subtract my number and subtract three I get my number plus one what is my number?

Lady bird [3.3K]

2 because once you double it, it becomes 4. Once you add 4, you get 8. When you subtract your number, which is 2, you get 6. Then when you subtract 3, you get 3. 3 is your number (2) plus 1

5 0

3 years ago