2 years ago

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Mathematics

2 answers:

Ipatiy [6.2K]2 years ago

4 0

Answer:

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Step-by-step explanation:

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Nitella [24]2 years ago

3 0

Answer:

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Step-by-step explanation:

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What is the 4th term in the sequence b(n)=1(-2)^n-1

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$b(n)=1(-2)^n-1$

When n = 4,
$b(4)=1(-2)^4-1$

$b(4)=16-1$

$b(4)=15$

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$b(n)=1(-2)^{n-1}$

When n = 4
$b(4)=1(-2)^{4-1}$

$b(4)=1(-2)^3$

$b(4)=1(-8)$

$b(4)=-8$

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