Answer:
5.4
Step-by-step explanation:
5.2, 5.4, 4.9, 4.4, 5.1
4.4, 4.9, 5.1, 5.2, 5.4
5.4 is the maximum
Hope this helped!
Answer:
identify-multiplication
Step-by-step explanation:
anything you multiply by 1 is most likely going to be in the identify property
Answer:
no
Step-by-step explanation:
the 2 fractions are not equal
Answer: 1) The best estimate for the average cost of tuition at a 4-year institution starting in 2020 =$ 31524.31
2) The slope of regression line b=937.97 represents the rate of change of average annual cost of tuition at 4-year institutions (y) from 2003 to 2010(x). Here,average annual cost of tuition at 4-year institutions is dependent on school years .
Step-by-step explanation:
1) For the given situation we need to find linear regression equation Y=a+bX for the given situation.
Let x be the number of years starting with 2003 to 2010.
i.e. n=8
and y be the average annual cost of tuition at 4-year institutions from 2003 to 2010.
With reference to table we get

By using above values find a and b for Y=a+bX, where b is the slope of regression line.

and

∴ To find average cost of tuition at a 4-year institution starting in 2020.(as n becomes 18 for year 2020 if starts from 2003 ⇒X=18)
So, Y= 14640.85 + 937.97×18 = 31524.31
∴The best estimate for the average cost of tuition at a 4-year institution starting in 2020 = $31524.31