Daniel is constructing boxes in the shape of triangular prism. How much cardboard is needed to make each box
1 answer:
Answer:
Area of cardboard required = 468 cm²
Step-by-step explanation:
Area of the cardboard required = Surface area of the triangular prism
Surface area of the triangular prism = Area of the lateral sides + Area of the triangular sides
Area of the one triangular side =
=
= 54 cm²
Area of lateral sides = Perimeter of the triangular base × Height
Perimeter of the triangular base = 9 + 12 + 15
= 36 cm
Now area of the lateral sides = (36) × 10
= 360 cm²
Surface area of the prism = 360 + 2(54)
= 360 + 108
= 468 cm²
Therefore, area of cardboard required for each box = 468 cm²
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Answer:
1) B = 66.5° c = 10.9
Step-by-step explanation:
I will do question one as an example. In general, for these questions you want to use the appropriate trigonometric ratios to solve for the variables and/or apply logic using rules regarding triangles. See attached image for all solving steps.
For side c, we can use Cosine of angle A for a ratio between 10 and c. When we write out the equation, we can solve for side c. So when we write it out, we get the equation:
cos23.5 = ¹⁰⁄c
c = ¹⁰⁄cos₂₃.₅
c = 10.9044 (make sure to round to the nearest tenth, which is one decimal place)
For angle B, since they have given two angles, you can solve for B since all angles of a triangle add up to 180 degrees.
So b = 180 - (90 + 23.5) = 180 - 113.5
b = 66.5
- It is also possible to solve this using sine of angle B and solve it from there, but applying the theory this way is much simpler. (this is on the image if you're curious about it)
I hope this helps you with the other 3 questions.
