Answer:
Upload the parallelogram or let me know if 5x-5 = 130 degrees and if it is one of the angles of the parallelogram.
The square root of 9 is 3. ✌️
Answer:
1/ sqrt(1+ln^2(x)) * 1/(ln^2x +1) * 1/x
Step-by-step explanation:
f(x) = sin (tan^-1 (ln(x)))
u substitution
d/du (sin u) * du /dx
cos (u) * du/dx
Let u =(tan^-1 (ln(x))) du/dx =d/dx (tan^-1 (ln(x)))
v substitution
Let v = ln x dv/dx = 1/x
d/dv (tan ^-1 v) dv/dx
1/( v^2+1) * dv/dx
=1/(ln^2x +1) * 1/x
Substituting this back in for du/dx
cos (tan^-1 (ln(x)) * 1/(ln^2x +1) * 1/x
We know that cos (tan^-1 (a)) = 1/ sqrt(1+a^2)
cos (tan^-1 (ln(x)) * 1/(ln^2x +1) * 1/x
1/ sqrt(1+ln^2(x)) * 1/(ln^2x +1) * 1/x
Answer:
x = 10
Step-by-step explanation:
2x/3 + 1 = 7x/15 + 3
<em><u>(times everything in the equation by 3 to get rid of the first fraction)</u></em>
2x + 3 = 21x/15 + 9
<em><u>(times everything in the equation by 15 to get rid of the second fraction)</u></em>
30x+ 45 = 21x + 135
<em><u>(subtract 21x from 30x; subtract 45 from 135)</u></em>
9x = 90
<em><u>(divide 90 by 9)</u></em>
x = 10
<h2>
Another solution:</h2>
2x/3 + 1 = 7x/15 + 3
<u><em>(find the LCM of 3 and 15 = 15)</em></u>
<u><em>(multiply everything in the equation by 15, then simplify)</em></u>
10x + 15 = 7x + 45
<u><em>(subtract 7x from 10x; subtract 15 from 45)</em></u>
3x = 30
<em><u>(divide 30 by 3)</u></em>
x = 10
(D) hope this helps kxjdndldjdkwpwnx