Answer:
(3,-3)
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
Area of a triangle:
![A=\frac{b*h}{2}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7Bb%2Ah%7D%7B2%7D)
In our case:
b=4
h=2
Plug in what we know:
![A=\frac{(4)(2)}{2} \\A=4units](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B%284%29%282%29%7D%7B2%7D%20%5C%5CA%3D4units)
Find the matching solution:
A.) it is 1/2 the area of a rectangle of length 4 units and width 2 units
X B.) it is twice the area of a rectangle of length 4 units and width two units
X C.) it is 1/2 the area of a square of side length 4 units
X D.) it is twice the area of a square of side length 4 units
I can give you as many sums as you want!
All of these sums are 15, just so you know.
0 + 15 = 15
1 + 14 = 15
2 + 13 = 15
3 + 12 = 15
4 + 11 = 15
5 + 10 = 15
6 + 9 = 15
7 + 8 = 15
8 + 7 = 15
9 + 6 = 15
10 + 5 = 15
11 + 4 = 15
12 + 3 = 15
13 + 2 = 15
14 + 1 = 15
15 + 0 = 15
Hope this helped!
Plz mark brainliest!
Answer:
i think the answer is a
Step-by-step explanation:
Given:
![\to \bold{-x -7y = 14}\\\\\to \bold{-4x -14y =28}\\\\](https://tex.z-dn.net/?f=%5Cto%20%5Cbold%7B-x%20-7y%20%3D%2014%7D%5C%5C%5C%5C%5Cto%20%5Cbold%7B-4x%20-14y%20%3D28%7D%5C%5C%5C%5C)
To find:
![\bold{x \ and \ y}=?](https://tex.z-dn.net/?f=%5Cbold%7Bx%20%5C%20and%20%5C%20y%7D%3D%3F)
Solution:
![\to \bold{-x -7y = 14}..................... (i) \\\\\to \bold{-4x -14y =28} .................(ii)\\\\](https://tex.z-dn.net/?f=%5Cto%20%5Cbold%7B-x%20-7y%20%3D%2014%7D.....................%20%28i%29%20%5C%5C%5C%5C%5Cto%20%5Cbold%7B-4x%20-14y%20%3D28%7D%20.................%28ii%29%5C%5C%5C%5C)
Solving the equation (i):
![\to \bold{-x -7y = 14} \\\\ \to \bold{-x= 14+7y} \\\\ \to \bold{x= - (14+7y)} \\\\](https://tex.z-dn.net/?f=%5Cto%20%5Cbold%7B-x%20-7y%20%3D%2014%7D%20%5C%5C%5C%5C%20%20%5Cto%20%5Cbold%7B-x%3D%20%2014%2B7y%7D%20%5C%5C%5C%5C%20%20%20%20%5Cto%20%5Cbold%7Bx%3D%20-%20%2814%2B7y%29%7D%20%5C%5C%5C%5C)
Putting the value of x into the equation (ii):
![\to \bold{-4(-(14+7y)) -14y =28} \\\\\to \bold{4(14+7y) -14y =28} \\\\\to \bold{56+28y -14y =28} \\\\\to \bold{56+14y =28} \\\\\to \bold{28+14y =0} \\\\\to \bold{14y =-28} \\\\\to \bold{y =\frac{-28}{14}} \\\\\to \bold{y =-2} \\\\](https://tex.z-dn.net/?f=%5Cto%20%5Cbold%7B-4%28-%2814%2B7y%29%29%20-14y%20%3D28%7D%20%5C%5C%5C%5C%5Cto%20%5Cbold%7B4%2814%2B7y%29%20-14y%20%3D28%7D%20%5C%5C%5C%5C%5Cto%20%5Cbold%7B56%2B28y%20-14y%20%3D28%7D%20%5C%5C%5C%5C%5Cto%20%5Cbold%7B56%2B14y%20%3D28%7D%20%5C%5C%5C%5C%5Cto%20%5Cbold%7B28%2B14y%20%3D0%7D%20%5C%5C%5C%5C%5Cto%20%5Cbold%7B14y%20%3D-28%7D%20%5C%5C%5C%5C%5Cto%20%5Cbold%7By%20%3D%5Cfrac%7B-28%7D%7B14%7D%7D%20%5C%5C%5C%5C%5Cto%20%5Cbold%7By%20%3D-2%7D%20%5C%5C%5C%5C)
Putting the value of y into the equation (i):
![\to \bold{-x -7(-2) = 14}\\\\\to \bold{-x +14 = 14}\\\\\to \bold{-x = 14-14}\\\\\to \bold{x = 0}\\\\](https://tex.z-dn.net/?f=%5Cto%20%5Cbold%7B-x%20-7%28-2%29%20%3D%2014%7D%5C%5C%5C%5C%5Cto%20%5Cbold%7B-x%20%2B14%20%3D%2014%7D%5C%5C%5C%5C%5Cto%20%5Cbold%7B-x%20%20%3D%2014-14%7D%5C%5C%5C%5C%5Cto%20%5Cbold%7Bx%20%20%3D%200%7D%5C%5C%5C%5C)
So, the value of ![\bold{x=0 \ and\ y= -2}\\\\](https://tex.z-dn.net/?f=%5Cbold%7Bx%3D0%20%5C%20and%5C%20%20y%3D%20-2%7D%5C%5C%5C%5C)
Learn more:
brainly.com/question/10151402