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2 years ago

9

CAN WE JUST TALKKK CAN WE JUST TALKKK CAN WE JUST MOVE A LITTLE SLOWER SO WE DONT GET LOST CANT WE JUST CANT WE JUST TALK SO WE

CAN MOVE SLOWER YAAAA

2 answers:

OlgaM077 [116]2 years ago

7 0

Answer:

oh wow XD

Step-by-step explanation:

Diano4ka-milaya [45]2 years ago

5 0

Ahahah ^-^

have a good day

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If you don’t know then don’t say anything.

tino4ka555 [31]

Answer:

in total there are 80 subjects. I don't know what class width is though.

Step-by-step explanation:

Look at the graph

3 0

2 years ago

The region bounded by y=(3x)^(1/2), y=3x-6, y=0

Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is $y = (3x)^{\frac{1}{2} }$

⇒ $y^{2} = 3x$ ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

$y^{2} - y - 6 = 0$

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = $\int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx$

= $\sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}$

= $[\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} } }{3}] - [13.5 - 18 - 6 + 12]$

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0

2 years ago

Which of the following equations have complex roots?

mestny [16]

Answer:

A

Step-by-step explanation:

Complex roots of quadratic functions occur when the <u>discriminant is negative</u>.

<u>Discriminant</u>

$b^2-4ac\quad\textsf{when}\:\:ax^2+bx+c=0$

Evaluate the discriminant of each of the given equations.

$\textsf{A.} \quad 3x^2+2=0$

$\implies a=3, \quad b=0, \quad c=2$

$\implies b^2-4ac=0^2-4(3)(2)=-24$

As -24 < 0 the equation will have complex roots.

$\textsf{B.} \quad 2x^2+1=7x$

$\implies 2x^2-7x+1=0$

$\implies a=2, \quad b=-7, \quad c=1$

$\implies b^2-4ac= (-7)^2-4(2)(1)=41$

As 41 > 0 the equation does not have complex roots.

$\textsf{C.} \quad 3x^2-1=6x$

$\implies 3x^2-6x-1=0$

$\implies a=3, \quad b=-6, \quad c=-1$

$\implies b^2-4ac=(-6)^2-4(3)(-1)=48$

As 48 > 0 the equation does not have complex roots.

$\textsf{D.} \quad 2x^2-1=5x$

$\implies 2x^2-5x-1=0$

$\implies a=2, \quad b=-5, \quad c=-1$

$\implies b^2-4ac=(-5)^2-4(2)(-1)=33$

As 33 > 0 the equation does not have complex roots.

Learn more about discriminants here:

brainly.com/question/27444516

brainly.com/question/27869538

Learn more about complex roots here:

brainly.com/question/26344541

6 0

2 years ago

Help me please beggin you

maw [93]

All we have to do is set this up!
we know that all he practiced altogether for 15 and 1/3 hours
so lets put that down so far
1
15 ----- =
3
and he says that the first week he played 6 and 1/4 hours on the first week
now lets add that
1 1
15 ----- = 6 ----- +
<span> 3 4
</span>now we also know that he played 4 and 2/3 hours on the first week
now lets add that
1 1 2
15 ----- = 6 ----- + 4 ----- +
<span> 3 4 3
</span>we arent finished yet!
now the third week we dont know how long he played so we are going to put x in its place
1 1 2
15 ----- = 6 ----- + 4 ----- + x
<span> 3 4 3
</span>and there is your answer! finally...
hope this helps:) MARK AS BRAINLIEST!!!
:D

5 0

2 years ago

What is 42.9 × 3.45 someone please

GaryK [48]

Answer:

148.005

Step-by-step explanation:

5 0

1 year ago