A mutation in a plant that could cause negative outcomes could be the plant has less leaves, or isn't hardy enough, like other plants. It would die. A plant from an area like Chernobyl, that has been affected by radiation could poison other animals, or pass that gene along, and ultimately kill that strand of plant.
Answer:
H. Haploid
Explanation:
A cell that contains two of each chromosome, or 2n, is a diploid. If a cell has half of those chromosomes, or just n, it is a haploid.
Answer:
(i) 1 moles of C
(ii) 4.5 moles of C
Explanation:
The Chemical equation is as follow,
A + 2 B → C
This chemical equation can be translated as;
(i) 1 mole of A reacts with 2 moles of B
(ii) 1 mole of A produces 1 mole of C
(iii) 2 moles of B reacts with 1 mole of A
(iv) 2 moles of B produces 1 mole of C
(v) 1 mole of C is produced by 1 mole of A and 2 moles of B
Therefore to find the number of moles of C produced by 2 mole of B we will do following proportional method.
As,
2 moles of B produced = 1 mole of C
So,
2 moles of B will produce = X moles of C
Solving for X,
X = 2 moles × 1 mole / 2 moles
X = 1 moles of C
Note:
In above problem the given moles were the same as that present in balance equation so incase if the moles are different from that of the equation then the method shown above can be used to solve it.
Lets try it for 9 moles of B:
As,
2 moles of B produced = 1 mole of C
So,
9 moles of B will produce = X moles of C
Solving for X,
X = 9 moles × 1 mole / 2 moles
X = 4.5 moles of C
Answer:
A. Some pea plants grow slowly and have few offspring
Explanation:
This contrast the reason why Mendel chose pea plants.
They grow rapidly and produce a lot of offspring.
<span>F- allele for freckles
f- </span><span>allele without freckles
1) The man is heterozygote and has freckles, its indicating that the allele for freckles is dominant.
A cross between him and a woman who is also </span><span>heterozygote: Ff x Ff
it would result in the following probabilities:
- 1/4 - homozygote with freckles: FF
- 2/4 - </span><span>heterozygote with freckles: Ff
- 1/4- </span><span>homozygote without freckles:ff
Their son would have a probability of 75% of being born with freckles.
2) The cross resulted in this probabilities:
</span><span><span>- 1/4 - homozygote with freckles: FF
- 2/4 - </span><span>heterozygote with freckles: Ff
- 1/4- </span><span>homozygote without freckles:ff
So, the chance of being born heterozygote for this gene is 2/4, which is the same as half (50%).
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