It has been a long time since I learned this but if I remember correctly Pp
Answer:
a. purple allele (C) = 0.609, pink allele (c) = 0.391
b. purple homozygotes = 371, pink homozygotes = 153, heterozygotes = 476
Explanation:
Given -
Purple flowers - 847
Pink flowers - 153
The frequency of recessive genotype i.e
![q^ 2 = \frac{153}{1000} \\q^ 2 = 0.153\\](https://tex.z-dn.net/?f=q%5E%202%20%3D%20%5Cfrac%7B153%7D%7B1000%7D%20%5C%5Cq%5E%202%20%3D%200.153%5C%5C)
Frequency of recessive allele i.e q is equal to
![q = \sqrt{0.153} \\q = 0.391](https://tex.z-dn.net/?f=q%20%3D%20%5Csqrt%7B0.153%7D%20%5C%5Cq%20%3D%200.391)
As per hardy Weinberg's first equilibrium equation -
![p + q = 1\\p = 1-q\\p = 1-0.391\\p = 0.609](https://tex.z-dn.net/?f=p%20%2B%20q%20%3D%201%5C%5Cp%20%3D%201-q%5C%5Cp%20%3D%201-0.391%5C%5Cp%20%3D%200.609)
Frequency of purple homozygous species
![= p^2\\= 0.609^2\\= 0.371](https://tex.z-dn.net/?f=%3D%20p%5E2%5C%5C%3D%200.609%5E2%5C%5C%3D%200.371)
Number of purple homozygous species ![= 0.371 * 1000= 371](https://tex.z-dn.net/?f=%3D%200.371%20%2A%201000%3D%20371)
Number of pink homozygous species ![= 0.153 * 1000= 153](https://tex.z-dn.net/?f=%3D%200.153%20%2A%201000%3D%20153)
Heterozygous species is equal to
![(1-0.371-0.153)* 1000\\= 0.476 * 1000\\= 476](https://tex.z-dn.net/?f=%281-0.371-0.153%29%2A%201000%5C%5C%3D%200.476%20%2A%201000%5C%5C%3D%20476)
Answer:
I think C. Petri dishes
Explanation:
"The most common growth media nutrient broths (liquid nutrient medium) or LB medium (Lysogeny Broth) are liquid. These are often mixed with agar and poured into Petri dishes to solidify. These agar plates provide a solid medium on which microbes may be cultured."-https://courses.lumenlearning.com/boundless-microbiology/chapter/culturing-bacteria/
I hope this helps!
Answer:
Distinct mechanisms are used by bacteria in order to transfer the gene from one bacteria to another. These are transformation, transduction, and conjugation. Transformation refers to the process of uptaking extracellular DNA by the recipient of the other bacterial cell.
In the process of transduction, the donor DNA gets packed within the bacteriophage and infects the recipient bacteria. In the process of conjugation, the genetic substance is transferred by the donor bacteria to the recipient via the process of mating.
a. Of all these three mechanisms, transformation is the process that exhibits a broad range and can be easily performed in the lab. As in the process, there is a slight chance of rejection or failure due to direct compatibility between the bacteria.
b. While the narrowest broad range is found in the process of conjugation, as in order to transfer the genetic substance between the two bacterial species, there should be a similarity between the two species so that they can mate and exchange the genetic substance in between them.