It is both true that <span>Technician A says that the excessive length of a heater hose is intended to protect the heater core from undue stress. Technician B says that excessive wear adds to the length of a heater hose, and a replacement heater hose should be roughly three to four inches shorter than its predecessor. So the asnwer is letter B.</span>
Letter B. is the answer
<span>B. Cell differentiation - start from a single cell and as the cells divide they become specialized</span>
HOPE THIS HELPS
Answer:
You just need to click over the desktop, move to the View, and then change to medium, if its the icon size.
However, if you feel your resolution requires screwing up, then you are required to do the right-click, and again over the Desktop and then move to the settings (screen resolution),
And if you by chance clicked on the magnifier utility, you can CTRL + ALT +DEL and you will also be required to shut the interface.
Explanation:
You just need to click over the desktop, move to the View, and then change to medium, if its the icon size.
However, if you feel your resolution requires screwing up, then you are required to do the right-click, and again over the Desktop and then move to the settings (screen resolution),
And if you by chance clicked on the magnifier utility, you can CTRL + ALT +DEL and you will also be required to shut the interface.
<span>#include <iostream>
using namespace std;
bool bears(int n);
int main(){
int number;
do{
cout<<"enter the amount of bears (press 0 to stop the program): ";
cin>>number;
if (bears(number)){
cout<<"you have reached the goal!"<<endl;
}
else{
cout<<"sorry, you have not reached the goal."<<endl;
}
}while(number != 0);
}
bool bears(int n){
if (n < 42){
return false;
}
else if (n == 42){
return true;
}
else{
if (n % 5 == 0){
return bears(n - 42);
}
else if(n % 2 == 0){
return bears(n / 2);
}
else if(n % 4 == 0|| n % 3 == 0)
{
int one;
int two;
one=n%10;
two=(n%100)/10;
return bears(n - one * two);
}
}
<span>}</span></span>
This is a named storage location in the computer's memory<span>. Byte code .</span>
