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dimulka [17.4K]
4 years ago
9

If your computers normal zoom is 100, but it looks like its at 500, how do you stop that? my invisioned thing isn't on, neither

is an accessebility. and right now, everything looks huge, I have to put the zoom on 50.
Computers and Technology
1 answer:
Alex Ar [27]4 years ago
7 0

Answer:

You just need to click over the desktop, move to the View, and then change to medium, if its the icon size.

However, if you feel your resolution requires screwing up, then you are required to do the right-click, and again over the Desktop and then move to the settings (screen resolution),

And if you by chance clicked on the magnifier utility, you can CTRL + ALT +DEL and you will also be required to shut the interface.

Explanation:

You just need to click over the desktop, move to the View, and then change to medium, if its the icon size.

However, if you feel your resolution requires screwing up, then you are required to do the right-click, and again over the Desktop and then move to the settings (screen resolution),

And if you by chance clicked on the magnifier utility, you can CTRL + ALT +DEL and you will also be required to shut the interface.

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Write a MIPS assembly language program that accomplishes the following tasks:The program will prompt the user to enter an intege
Svetlanka [38]

Answer:

Here's the code below

Explanation:

# All the comment will start with #

# MIPS is assembly language program.

# we store the all the data inside .data

.data:

k: .asciiz "Enter the kth value:\n"

.text

.globl main

li $s0, 0 # $s0 = 0

li $t0, 0 # $t0 = 0

la $n0, k # $n0 is kth value address

syscall # call print_string()

li $v0, 0 # $v0

syscall

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addi $sp, $sp, -4 # move the stack pointer down

sw $ra, 0 ($sp) # save the return address for main

jal fncheck # call fncheck(n);

fncheck:

beq $n, 0, fnfirst #if n==0 then fnfirst

beq $n, 0, fnfirst #if n==0 then fnfirst

ble $n0, 5, fnrec # if (n <=5) then 5

bge $n0, 5, fnjoke

#first function for n 0 and 1

fnfirst:

li $t0, 0 # initialize $t0 = 0

addi $t0, $t0, 20 # $t0 = 20

move $v0, $t0 # return 20

jr $ra

#function to execute 5*function1(n-2) + n;

fnrec:

sub $sp, $sp, 12 # store 3 registers

sw $ra, 0($sp) # $ra is the first register

sw $n0, 4($sp) # $n0 is the second register

addi $n0, $n0, -2 # $a0 = n - 2

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lw $n0, 4($sp) # retrieve original value of n

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add $v0, $v0, $t0

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4 0
4 years ago
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Answer:

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    first=name1;

else

    //assign name2 to first, if the

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    first=name2;

5)

//compare name1 and name2

    if(strcmp(name1,name2)>0)

   

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Explanation:

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