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3 years ago

5

In the picture below a speaker is emitting a sound toward a solid barrier with a gap in it. Diagram and label the two types of w

ave interactions.

1 answer:

mojhsa [17]3 years ago

5 0

Answer: sound waves and mechanical waves or mechanical energy

Step-by-step explanation:

You might be interested in

From the table below create an equation.

Bond [772]

Answer:

Step-by-step explanation:

2,4 ,10,12,19,36.5,40

4 0

2 years ago

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of

tresset_1 [31]

Because I've gone ahead with trying to parameterize $S$ directly and learned the hard way that the resulting integral is large and annoying to work with, I'll propose a less direct approach.

Rather than compute the surface integral over $S$ straight away, let's close off the hemisphere with the disk $D$ of radius 9 centered at the origin and coincident with the plane $y=0$ . Then by the divergence theorem, since the region $S\cup D$ is closed, we have

$\displaystyle\iint_{S\cup D}\vec F\cdot\mathrm d\vec S=\iiint_R(\nabla\cdot\vec F)\,\mathrm dV$

where $R$ is the interior of $S\cup D$ . $\vec F$ has divergence

$\nabla\cdot\vec F(x,y,z)=\dfrac{\partial(xz)}{\partial x}+\dfrac{\partial(x)}{\partial y}+\dfrac{\partial(y)}{\partial z}=z$

so the flux over the closed region is

$\displaystyle\iiint_Rz\,\mathrm dV=\int_0^\pi\int_0^\pi\int_0^9\rho^3\cos\varphi\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=0$

The total flux over the closed surface is equal to the flux over its component surfaces, so we have

$\displaystyle\iint_{S\cup D}\vec F\cdot\mathrm d\vec S=\iint_S\vec F\cdot\mathrm d\vec S+\iint_D\vec F\cdot\mathrm d\vec S=0$

$\implies\boxed{\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=-\iint_D\vec F\cdot\mathrm d\vec S}$

Parameterize $D$ by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec k$

with $0\le u\le9$ and $0\le v\le2\pi$ . Take the normal vector to $D$ to be

$\vec s_u\times\vec s_v=-u\,\vec\jmath$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_D\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^9\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_u\times\vec s_v)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_0^9(u^2\cos v\sin v\,\vec\imath+u\cos v\,\vec\jmath)\cdot(-u\,\vec\jmath)\,\mathrm du\,\mathrm dv$

$=\displaystyle-\int_0^{2\pi}\int_0^9u^2\cos v\,\mathrm du\,\mathrm dv=0$

$\implies\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\boxed{0}$

8 0

3 years ago

A car rental company charges $34 per day for a rented car and $0.50 for every mile driven. A second car rental company charges $

Ludmilka [50]

Answer:

B 2/3

Step-by-step explanation:

:)

5 0

2 years ago

Read 2 more answers

Which inequality represents all the solutions of -5x + 5 ≥ 160 − 10x? A. x ≤ -33 B. x ≥ 33 C. x ≥ 31 D. x ≤ 31

ikadub [295]

Answer:

The answer is B.

Step-by-step explanation:

Solve for x.

-5x + 5 $\geq$ 160 - 10x

Add 10x to both sides, and subtract 5 from both sides.

5x $\geq$ 155

Now, divide by 5.

x $\geq$ 31 is the answer

#teamtrees #WAP (Water And Plant)

3 0

3 years ago

Read 2 more answers

Greg is practicing for a marathon to start he ran 2 miles around the track he wants to know how many yards this is how many yard

IgorC [24]

Answer:

3520 yards

Step-by-step explanation:

1 mile = 1760 yards

2 miles = 2(1760)=3520 yards

3 0

3 years ago