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3 years ago

Please answer down below and please use all the boxes

Mathematics

1 answer:

vitfil [10]3 years ago

4 0

Answer:

Step-by-step explanation:

364

318

all of the answers are in order of the boxes

hope this helps <3

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At PRMS, 25% of the 124 students Mrs. Pasternak teaches buy their lunches in the cafeteria. How many students buy their lunches

Ksju [112]

25% = 0.25
124 x 0.25 = 31

31 students bought their lunch.

Part = 31
Percent = 25%
Whole = 124

Hope this helps! ✨

6 0

3 years ago

HELP MATH QUESTION PRE CAL

Zarrin [17]

Use the pythagorean theorem. It would be set up as
a^2 + 3.7^2 = 4.0^2

8 0

3 years ago

What information is necessary to prove the triangles congruent by SAS?

Ber [7]

Answer:

SAS requires two congruent sides and the included angle be also congruent

Given is the picture are congruent triangles

<u>ΔACB ≅ ΔECD, because:</u>

AC ≅ EC, given
BC ≅ DC, given
∠ACB ≅ ∠ECD, vertical angles

5 0

3 years ago

Read 2 more answers

assume that when adults with smartphones are randomly selected 15 use them in meetings or classes if 15 adult smartphones are ra

Tanzania [10]

Answer:

The probability that at least 4 of them use their smartphones is 0.1773.

Step-by-step explanation:

We are given that when adults with smartphones are randomly selected 15% use them in meetings or classes.

Also, 15 adult smartphones are randomly selected.

Let X = <em>Number of adults who use their smartphones</em>

The above situation can be represented through the binomial distribution;

$P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; n = 0,1,2,3,.......$

where, n = number of trials (samples) taken = 15 adult smartphones

r = number of success = at least 4

p = probability of success which in our question is the % of adults

who use them in meetings or classes, i.e. 15%.

So, X ~ Binom(n = 15, p = 0.15)

Now, the probability that at least 4 of them use their smartphones is given by = P(X $\geq$ 4)

P(X $\geq$ 4) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

= $1- \binom{15}{0}\times 0.15^{0} \times (1-0.15)^{15-0}-\binom{15}{1}\times 0.15^{1} \times (1-0.15)^{15-1}-\binom{15}{2}\times 0.15^{2} \times (1-0.15)^{15-2}-\binom{15}{3}\times 0.15^{3} \times (1-0.15)^{15-3}$

= $1- (1\times 1\times 0.85^{15})-(15\times 0.15^{1} \times 0.85^{14})-(105 \times 0.15^{2} \times 0.85^{13})-(455 \times 0.15^{3} \times 0.85^{12})$

= <u>0.1773</u>

3 0

4 years ago

We are given arc KL is 12x+4, arc KJ is 8x-6, and angle E is 99 degrees. What is the actual degree measure of arc KJ? *

Svetlanka [38]

The actual degree measure of arc KJ is 99 degrees

<h3>Circle geometry</h3>

From the given informtion

arc KL = 12x+4

arc KJ = 8x-6

<E = 99 degrees

The equation required to get the value of "x" is given as:

12x + 4 + 8x - 6 + 99 = 360

20x + 97 = 360

20x = 360 - 97

20x = 263

x = 13.15

For the arcKL

arcKJ = 8(13.15) - 6

arcKJ = 99degrees

HEnce the actual degree measure of arc KJ is 99 degrees

learn more on circle geometry here: brainly.com/question/24375372

5 0

3 years ago