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monitta
3 years ago
10

Find the 22nd term of the arithmetic sequence whose common difference is d =3 and whose first term is a_1=-20

Mathematics
1 answer:
Ivenika [448]3 years ago
4 0
1,4,7,10,13,16,19,22,25,28,31,34,37,40,43,46,49,52,55,58,61,64,67,70,73,76,79,82,85,88,91,94,97,100

f(n) = 1 + 3(n-1) = 1 + 3n - 3 = 3n -2

f(22) = 3(22)-2 = 66-2 = 64
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A sequence has the recursive definition f(1)= 2/3, f(n)= f(n-1)•
Advocard [28]
Answer:

Explanation:

f(3) = (3 - 1) • 3/2
f(3) = 2 • 3/2
f(3) = 3

f(4) = (4 - 1) • 3/2
f(4) = 3 • 3/2
f(4) = 9/2

f(5) = (5-1) • 3/2
f(5) = 4 • 3/2
f(5) = 6

f(6) = (6-1) • 3/2
f(6) = 5 • 3/2
f(6) = 15/2

f(7) = (7-1) • 3/2
f(7) = 6 • 3/2
f(7) = 9
8 0
3 years ago
Given triangle JKL,write the coordinates of the vertices of a triangle J’K’L’ that result from a translation of triangle JKL two
sweet [91]

Step-by-step explanation:

since I don't have any data about the coordinates, I am simply calling them xj, yj, and xj' and yj'.

J = (xj, yj)

K = (xk, yk)

L = = (xl, yl)

a translation (shift) 2 units to the left just means, that the y coordinates regain the same, but the x coordinates are decreased ("to the left" = getting smaller) by 2.

J' = (xj - 2, yj)

K' = (xk - 2, yk)

L' = (xl - 2, yl)

7 0
1 year ago
Find all factors of 2x^3-3x^2-2x
Nesterboy [21]

ANSWER:

x, 2x + 1, x -2

STEP-BY-STEP EXPLANATION:

We have the following expression:

2x^3-3x^2-2x

We simplify as follows to determine the factors:

\begin{gathered} \text{ We factor the common term:} \\  \\ x\left(2x^2-3x-2\right) \\  \\ \text{ Now we factor the following term} \\  \\ 2x^2-3x-2 \\  \\ -3x=x-4x \\  \\ 2x^2+x-4x-2 \\  \\ \left(2x^2+x\right)+\left(-4x-2\right) \\  \\ x\left(2x+1\right)-2\left(2x+1\right) \\  \\ \left(2x+1\right)\left(x-2\right) \\  \\ \text{ Therefore:} \\  \\ 2x^3-3x^2-2x=x\left(2x+1\right)\left(x-2\right) \end{gathered}

The factors would be x, 2x + 1, x -2

7 0
1 year ago
Which expression is equivalent to 7(4+7)? *
Mashcka [7]

Answer:

28+49

Step-by-step explanation:

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