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3 years ago

Find the 22nd term of the arithmetic sequence whose common difference is d =3 and whose first term is a_1=-20

1 answer:

4 0

1,4,7,10,13,16,19,22,25,28,31,34,37,40,43,46,49,52,55,58,61,64,67,70,73,76,79,82,85,88,91,94,97,100

f(n) = 1 + 3(n-1) = 1 + 3n - 3 = 3n -2

f(22) = 3(22)-2 = 66-2 = 64

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What is the inverse and restricted domain of the equation 8x^2-3

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Answer: $\bold{y=\pm \dfrac{\sqrt{2(x+3)}}{4},\qquad x\neq -3}$

Step-by-step explanation:

y = 8x² - 3 (Restriction: none - x is All Real Numbers)

The inverse is when you swap the x's and y's and then solve for y

x = 8y² - 3 swapped the x and y

x + 3 = 8y² added 3 to both sides

$\dfrac{x+3}{8}=y^2$ divided both sides by 8

$\sqrt{\dfrac{x+3}{8}}=\sqrt{y^2}$ square rooted both sides

$\pm \sqrt{\dfrac{x+3}{8}}=y$ simplified

$\pm \sqrt{\dfrac{x+3}{8}\bigg(\dfrac{2}{2}\bigg)}=y$ rationalized the denominator

$\pm \sqrt{\dfrac{2(x+3)}{16}}=y$ simplified

$\pm \dfrac{\sqrt{2(x+3)}}{4}=y$ simplified

Restriction:

The radical (inside the square root sign) cannot be negative

→ 2(x + 3) ≥ 0

x + 3 ≥ 0 divided both sides by 2

x ≥ -3 subtracted 3 from both sides

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