Answer:
1.8% or 1.818181%
Step-by-step explanation:
If in a batch of 440 water purifiers, we find 8 to be defective.
Then the probability of the next purifier being defective is 8/440
In percentage = 8/440 * 100
=> 8/44 * 10
=> 8/22 * 5
=> 40/22
=> 20 / 11
20/11 is roughly 1.8181818
Rounding it to the nearest tenth, we get 1.8%
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Answer:
10000 = 1 x 104
Step-by-step explanation:
Answer:
f(-2) = 4
Step-by-step explanation:
The function has three definitions depending on the value of x.
You are looking for the value of the function at x = -2.
-2 is in the interval x <= -1, which is the first line of the definition of the function.
We use the first line of the definition of the function.
f(x) = -2x for x <= -1
f(-2) = -2(-2) = 4
Answer: f(-2) = 4
Let's start by assuming Armando's house is between Joey's and the park.
Let

be the distance Joey walked to Armando's house.
<span>The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park.
</span>


That's probably the answer they're looking for. But what if the park is between Joey and Armando's houses or Joey is between the park and Armando? (The latter isn't really possible with the given distances.)
Let

be the distances between three collinear points like we have here. Our equation is really a few equations in one, something like

Let's get rid of the plus/minuses. Squaring,



For us, that's a quadratic equation for


I'll skip right to the solutions,


We could have gotten the 3/2 just by adding 9/10+3/5 but this was more fun.