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valina [46]
3 years ago
15

How these ratios alike? 8:5 16:10 24:15

Mathematics
1 answer:
arlik [135]3 years ago
6 0

Answer:

All the left numbers of the Ratio go by 8's times tables and all the right numbers go by 5's times tables

Step-by-step explanation:

8x1= 8

8x2 =16

8x3 = 24

5x1= 5

5x2= 10

5x3= 15

Let me know if its right.

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What is the product of (3x+5) and (x+4)
kodGreya [7K]

For this case we must find the product of (3x + 5) (x + 4)

By definition, the distributive property states that:

(a + b) (c + d) = ac + ad + bc + bd

Then, according to the expression we have:

3x ^ 2 + 12x + 5x + 20 =\\3x ^ 2 + 17x + 20

Answer:

3x ^ 2 + 17x + 20

Option C

4 0
3 years ago
Read 2 more answers
Find the point-slope equation for the line that passes through the points (5,19) and (-5,-1).
xxTIMURxx [149]

Answer: y - 19 = 2(x - 5)

Step-by-step explanation:

The point slope form is expressed as

y - y1 = m(x - x1)

Where

m represents slope

Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis

change in the value of y = y2 - y1

Change in value of x = x2 -x1

y2 = final value of y

y 1 = initial value of y

x2 = final value of x

x1 = initial value of x

The given points are (5,19) and (-5,-1)

y2 = - 1

y1 = 19

x2 = - 5

x1 = 5

Slope,m = (- 1 - 19)/(- 5 - 5) = - 20/- 10 = 2

To determine the equation, we would substitute x1 = 5, y1 = 19 and m= 2 into the point slope form equation. It becomes

y - 19 = 2(x - 5)

7 0
3 years ago
Read 2 more answers
Help pls ! 15−24÷4⋅2
Nady [450]

Answer:

9.28

Step-by-step explanation:

hope this help!!!

8 0
3 years ago
Four friends go out to lunch and decide to split the bill evenly. The bill comes to $48.20. How much does each person owe?
jeka94
Four friends go out to lunch and they agree to split the bill evenly.
so now you have to divide the price by 4 because there's four people.
$48.20. / 4.
so your answer is $12.05 that's so much each person will pay for their share of bill.
8 0
3 years ago
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For what value of c is the function defined below continuous on (-\infty,\infty)?
kozerog [31]
f(x)= \left \{ {{x^2-c^2,x \ \textless \  4} \atop {cx+20},x \geq 4} \right


It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
<span>A function, f, is continuous at x = 4 if 
</span><span>\lim_{x \rightarrow 4} \  f(x) = f(4)

</span><span>In notation we write respectively
</span>\lim_{x \rightarrow 4-} f(x) \ \ \ \text{ and } \ \ \ \lim_{x \rightarrow 4+} f(x)

Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just <span>4c + 20.
</span>
On the other hand, for x < 4, f(x) = x^2 - c^2. Hence 
\lim_{x \rightarrow 4-} f(x) = \lim_{x \rightarrow 4-} (x^2 - c^2) = 16 - c^2

Thus these two limits, the one from above and below are equal if and only if
 4c + 20 = 16 - c²<span> 
 Or in other words, the limit as x --> 4 of f(x) exists if and only if
 4c + 20 = 16 - c</span>²

c^2+4c+4=0&#10;\\(c+2)^2=0&#10;\\c=-2

That is to say, if c = -2, f(x) is continuous at x = 4. 

Because f is continuous for all over values of x, it now follows that f is continuous for all real nubmers (-\infty, +\infty)

4 0
3 years ago
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