All categories

2 years ago

I don't remember sector area, and this is on my review for my geometry final

Mathematics

1 answer:

Fantom [35]2 years ago

8 0

$\bf \textit{area of a sector of a circle}\\\\
A=\cfrac{\theta\pi r^2}{360}\qquad 
\begin{cases}
\theta=\textit{angle in degrees}\\
r=radius\\
---------\\
\theta=45\\
r=8
\end{cases}\implies A=\cfrac{45\cdot \pi \cdot 8^2}{360}$

You might be interested in

-1. The table shows the annual consumption of cheese per person in the United States for selected years in the 20th century. Let

olga nikolaevna [1]

<span>Using processing software (Excel) or even a decent scientific calculator. You input the values and generate the best fit cubic equation.
For number 1, the equation is
y = 8x10</span>⁻⁵ x³ - 0.0097 x² + 0.374 x + 1.083
where x is the number of years since 1900
y is the pounds cheese consumed

For number 2, the equation is
y = -3x10⁻⁵ x³ + 0.0028 x² + 0.2155 x + 1.7736

For number 3
P(-1) = 18

5 0

3 years ago

Help ASAP!!!<br> Please and thank you so much

PilotLPTM [1.2K]

Rectangle on the left = 3 × 4 = 12

Rectangle in the middle = 3 × 2 = 6

Rectangle on the right = 4 × 3 = 12

Add:

12 + 6 + 12 = 30

Answer = 30

Hope this helped☺☺

8 0

3 years ago

Read 2 more answers

What is the actual distance of 23cm

Vera_Pavlovna [14]

Answer:

23 cm = 0.23 m or 9.055118 inches

Step-by-step explanation:

5 0

3 years ago

Last Sunday a certain store sold copies of 256 Newspaper A for $1.00 each and copies of Newspaper B for $1.25 each, and the stor

Marat540 [252]

Answer:

D. $\frac{400p}{500-p}$

Step-by-step explanation:

let's call A the number of copies sold of newspaper A and B the number of copies sold of newspaper B.

So, we can formulate the following equations from the sentence: a certain store sold copies of 256 Newspaper A for $1.00 each and copies of Newspaper B for $1.25 each as:

A + B = 256 (1)

1A + 1.25 B = Total Revenue (2)

Then, r and p are equal to:

$r=\frac{A}{Total Revenue}*100=\frac{100A}{A+1.25B}$ (3)

$p=\frac{A}{256} *100=\frac{100A}{256}$ (4)

Isolating A from (4) and B from (1), we get:

$A=\frac{256p}{100} =2.56p$ (5)

$B=256-A=256-2.56p$ (6)

Finally, replacing (5) and (6) in (3), we get:

$r=\frac{100A}{A+1.25B}=\frac{100(2.56p)}{2.56p+1.25(256-2.56p)}\\\\r=\frac{256p}{2.56p+320-3.2p}=\frac{256p}{320-0.64p}\\\\r=\frac{256p/0.64}{(320-0.64p)/0.64}=\frac{400p}{500-p}$

7 0

3 years ago

Both figures shown below are trapezoids. ABCD - WXYZ. Find the

ivolga24 [154]

Answer:

Y*x -2x=40min

7 0

3 years ago