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Jobisdone [24]
2 years ago
14

I don't remember sector area, and this is on my review for my geometry final

Mathematics
1 answer:
Fantom [35]2 years ago
8 0
\bf \textit{area of a sector of a circle}\\\\
A=\cfrac{\theta\pi r^2}{360}\qquad 
\begin{cases}
\theta=\textit{angle in degrees}\\
r=radius\\
---------\\
\theta=45\\
r=8
\end{cases}\implies A=\cfrac{45\cdot \pi \cdot 8^2}{360}
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3 years ago
Help ASAP!!!<br> Please and thank you so much
PilotLPTM [1.2K]
Rectangle on the left = 3 × 4 = 12

Rectangle in the middle = 3 × 2 = 6

Rectangle on the right = 4 × 3 = 12

Add:

12 + 6 + 12 = 30

Answer = 30

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Step-by-step explanation:

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3 years ago
Last Sunday a certain store sold copies of 256 Newspaper A for $1.00 each and copies of Newspaper B for $1.25 each, and the stor
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Answer:

D. \frac{400p}{500-p}

Step-by-step explanation:

let's call A the number of copies sold of newspaper A and B the number of copies sold of newspaper B.

So, we can formulate the following equations from the sentence: a certain store sold copies of 256 Newspaper A for $1.00 each and copies of Newspaper B for $1.25 each as:

A + B = 256                               (1)

1A + 1.25 B = Total Revenue    (2)

Then, r and p are equal to:

r=\frac{A}{Total Revenue}*100=\frac{100A}{A+1.25B}     (3)

p=\frac{A}{256} *100=\frac{100A}{256}                            (4)

Isolating A from (4) and B from (1), we get:

A=\frac{256p}{100} =2.56p                (5)

B=256-A=256-2.56p                         (6)

Finally, replacing (5) and (6) in (3), we get:

r=\frac{100A}{A+1.25B}=\frac{100(2.56p)}{2.56p+1.25(256-2.56p)}\\\\r=\frac{256p}{2.56p+320-3.2p}=\frac{256p}{320-0.64p}\\\\r=\frac{256p/0.64}{(320-0.64p)/0.64}=\frac{400p}{500-p}

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