The length of a rectangle is shown below:

Mathematics

2 answers:

kicyunya [14]3 years ago

8 0

Answer:

b mark me brainliest

Step-by-step explanation:

KIM [24]3 years ago

5 0

Answer: It would be C(-3 -1) D(1 -1). (Aka the second one)

Step-by-step explanation:

The top of A and B is 4 units. If you count down five units vertically you get to -3, -1 and 1, -1. You need to count down 5 units because its asking you to get 20. So 5 x 4 = 20.

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Can someone help me work out question 3?

Nezavi [6.7K]

To find the point of intersection, we want to set the two equations equal to each other to find where they meet. The problem is, we have two variables, which means we can't just set them equal to each other as is. We need to manipulate the equations so that we can remove one of the variables at a time to solve for the other one.

First, let's move y to one side so we can solve for x.
2x-3y=9
2x-9=3y
y=(2x-9)/3

5x+4y=11
4y=11-5x
y=(11-5x)/4

Now that they both equal the same thing (y), we can set them equal to each other and solve for x. This will give us the x value for the point of intersection of the lines.
(11-5x)/4=(2x-9)/3
3(11-5x)=4(2x-9)
33-15x=8x-36
33+36=8x+15x
69=23x
x=69/23
x=3

Now, we can do the opposite, and solve for x to find the y coordinate.
2x-3y=9
2x=3y+9
x=(3y+9)/2

5x+4y=11
5x=11-4y
x=(11-4y)/5

(3y+9)/2=(11-4y)/5
5(3y+9)=2(11-4y)
15y+45=22-8y
15y+8y=22-45
23y= -23
y= -1

The coordinates for the point of intersection of the two lines is (3, -1).

5 0

4 years ago

The following tables each show the inventory of a warehouse and the number of orders for four different products which have been

snow_lady [41]

Orders: x
Inventory: y

1) First table
x2-x1=6-3→x2-x1=3
y2-y1=1920-1960→y2-y1=-40

x3-x2=9-6→x3-x2=3=x2-x1
y3-y2=1900-1920→y3-y2=-20 different to y2-y1=-40. The table does not represent a linear relationship.

2) Second table
x2-x1=7-5→x2-x1=2
y2-y1=1860-1900→y2-y1=-40

x3-x2=9-7→x3-x2=2=x2-x1
y3-y2=1820-1860→y3-y2=-40=y2-y1

x4-x3=11-9→x4-x3=2=x3-x2
y4-y3=1780-1820→y4-y3=-40=y3-y2

x5-x4=13-11→x5-x4=2=x4-x3
y5-y4=1740-1780→y5-y4=-40=y4-y3

The table represents a linear relationship.

3) Third table
x2-x1=2-1→x2-x1=1
y2-y1=1000-2000→y2-y1=-1000

x3-x2=3-2→x3-x2=1=x2-x1
y3-y2=500-1000→y3-y2=-500 different to y2-y1=-1000. The table does not represent a linear relationship.

4) Fourth table
x2-x1=6-4→x2-x1=2
y2-y1=1640-1840→y2-y1=-200

x3-x2=8-6→x3-x2=2=x2-x1
y3-y2=1360-1640→y3-y2=-280 different to y2-y1=-200. The table does not represent a linear relationship.

Answer: The second table best represents a linear relationship.

8 0

4 years ago

Read 2 more answers

Please help! I need this asap! Thank you. (^-^)

FrozenT [24]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

PLEASE ANSWER! Given the functions f(x) = x2 + 6x - 1, g(x) = -x2 + 2, and h(x) = 2x2 - 4x + 3, rank them from least to greatest

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