Answer:
The bolts with diameter less than 5.57 millimeters and with diameter greater than 5.85 millimeters should be rejected.
Step-by-step explanation:
We have been given that the diameters of bolts produced in a machine shop are normally distributed with a mean of 5.71 millimeters and a standard deviation of 0.08 millimeters.
Let us find the sample score that corresponds to z-score of bottom 4%.
From normal distribution table we got z-score corresponding to bottom 4% is -1.75 and z-score corresponding to top 4% or data above 96% is 1.75.
Upon substituting these values in z-score formula we will get our sample scores (x) as:


Therefore, the bolts with diameters less than 5.57 millimeters should be rejected.
Now let us find sample score corresponding to z-score of 1.75 as upper limit.


Therefore, the bolts with diameters greater than 5.85 millimeters should be rejected.
A=3B
4.35A+5.40B=780.95
Substitute 3B into A for the second equation:
4.35(3B)+5.40B=780.90
13.05B+5.40B=780.90
18.45B=780.90
B=42.33
Plug into equation 1:
A=3B
A=3(42.33)
A=126.98
Given:


To find:
The value of
.
Solution:
We have,
![[\because d(t)=80t]](https://tex.z-dn.net/?f=%5B%5Cbecause%20d%28t%29%3D80t%5D)

Now,
![[\because C(d)=0.09d]](https://tex.z-dn.net/?f=%5B%5Cbecause%20C%28d%29%3D0.09d%5D)

Therefore, the value of
is 72.