Answer:
(-8^3)^2
=-8^2*3
=-8^6
=1/8^6
=1/262144
Step-by-step explanation:
Answer:
- <em>The probability that the second favorite character will die given that the first favorite character dies is</em><u> 0.53</u>
- <u>This kind of probability is called conditional probability</u>
Explanation:
Name the events and their probabiities:
- Event A: her favorite character will survive, so P (A) = 0.70
- Event B: her her second favorite character will die, so P(B) = 0.75
- Both characters will die ⇒ P (B and not A) = 0.16
You want to find P (B | not A).
That is the probability of the succes B (the second favorite character will die) given other event (not A or the first favorite character dies) is certain (it happens) and that is called conditional probability.
- P (not A) is the complement probability of A, so P (not A) = 1 - P(A) = 1 - 0.7 = 0.3
So, you have P(B), P(not A) and want to find P (B | not A)
The definition of conditional probability is:
- P (X | Y) = P (X and Y) / P (Y)
So, replacing with our terms, we get:
- P ( B | not A) = P (B and not A) / P (not A) = 0.16 / 0.3 ≈ 0.53
Answer:
525 $
Step-by-step explanation:
Amount borrowed = $2500
Rate = 7%
Time = 3 years
therefor interest = $2500 X 7/100 X 3
Hope it help You
Answer:
We must order these decimals from least to greatest. Then we must determine how the least compares with the winning score.
9.80 -> 3
9.75 -> 1
9.79 -> 2
9.81 -> 4
The least decimal is 9.75. Now we must determine how 9.75 compare with the winning score.
The last swimmer must get a score less than 9.75 seconds in order to win.
Answer:
1) The solve by graphing will the preferred choice when the equation is complex to be easily solved by the other means
Example;
y = x⁵ + 4·x⁴ + 3·x³ + 2·x² + x + 3
2) Solving by substitution is suitable where we have two or more variables in two or more (equal number) of equations
2x + 6y = 16
x + y = 6
We can substitute the value of x = 6 - y, into the first equation and solve from there
3) Solving an equation be Elimination, is suitable when there are two or more equations with coefficients of the form, 2·x + 6·y = 23 and x + y = 16
Multiplying the second equation by 2 and subtracting it from the first equation as follows
2·x + 6·y - 2×(x + y) = 23 - 2 × 16
2·x - 2·x + 6·y - 2·y = 23 - 32
0 + 4·y = -9
4) An example of a linear system that can be solved by all three methods is given as follows;
2·x + 6·y = 23
x + y = 16
Step-by-step explanation:
