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Rzqust [24]
3 years ago
15

Look at this set of ordered pairs: (14, 19) (14, 5) (4, 18) Is this relation a function? yes no​

Mathematics
1 answer:
Vitek1552 [10]3 years ago
5 0

Answer:

This is a relationship, and NOT a function

Step-by-step explanation:

Notice that from the pairs listed, we find that the number 14 in the Domain is connected via the relationship with TWO different numerical values in the Range (with 19 and with 5).Therefore, this cannot be a function, since in such case, each element of the Domain must connect with no more than one element of the Range.

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SSSSS [86.1K]

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Step-by-step explanation:

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Step by step<br> Please urgent
kotegsom [21]

Answer:

Below in bold.

Step-by-step explanation:

1) ( a^2 + b^2 = (a + b)^2 - 2ab

= 29 - 2(6)

= 29-12

= 17.

2).  (x - y)^2 = x^2 + y^2 - 2xy

so 20 = 18 - 2xy

2xy = 18-20 = -2

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3). 1/x + x = 7

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= 1/x^2 + x^2 + 2

But(1/x + x)^2 = 7^2 = 49

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6 0
3 years ago
Samantha evaluates the expression -5.3 + 7.9 and gets an answer of 2.4
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Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
F(x)=3x−4g(x)=−x2+2x−5h(x)=2x2+1j(x)=6x2−8xk(x)=3x2−x+7 Calculate (fh)(x).
elena-s [515]

Answer:

( f h ) (x)  = 6 x² - 1

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given<em> f(x)   =  3 x - 4</em>

         g (x)  = −x²+2 x−5

      <em>   h (x)  = 2 x² + 1</em>

         j (x)    = 6 x + 2 - 8 x

        K (x)   = 3 x² - x + 7

<u><em>Step(ii)</em></u>:-

<em>( f h ) (x) = f ( h (x)) = f ( 2 x² + 1 )</em>

                            =  3 (2 x² + 1 ) - 4

                            =  3 ((2 x² ) + 3 - 4

                           =   <em>6 x² - 1</em>

<u><em> Final answer:</em></u>-

∴ <em> ( f h ) (x)  = 6 x² - 1</em>

3 0
3 years ago
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