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laiz [17]
3 years ago
15

What is the hypothesis in the following conditional

Mathematics
1 answer:
xeze [42]3 years ago
8 0
The answers is Triangle
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Given each pair of similar triangles find the missing value. of LJK=PQR find x
Svetlanka [38]

Answer:

1

Step-by-step explanation:

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Explain the relationship between angle W and angles X and Y.
Dmitrij [34]

Answer: w is equal to the sum of angles x and y. (W=x+y)

Step-by-step explanation:

The exterior angle of a triangle (in this case w) is equal to the sum of the two remote interior angles of the triangle (in this case angles x and y)

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2 years ago
a cylinder has a height of 9 cm and a radius of 15 cm what is the exact volume A( 225 pi B( 405 pi C(675 pi D( 90 pi
egoroff_w [7]
The answer is for this question would obviously be D.
7 0
3 years ago
What is 42% of 75?<br> A. <br> 315<br> B. <br> 105<br> C. <br> 31.5<br> D. <br> 10.5
iragen [17]

Answer:

31.5

Step-by-step explanation:

42% of 75 is 31.5. The working is as follows :

<em>42</em><em> </em><em>÷</em><em> </em><em>100</em><em> </em><em>×</em><em> </em><em>75</em><em> </em><em>=</em><em> </em><em>31</em><em>.</em><em>5</em>

<em>You</em><em> </em><em>can</em><em> </em><em>also</em><em> </em><em>use</em><em> </em><em>the</em><em> </em><em>picture</em><em> </em><em>^</em><em>^</em>

7 0
3 years ago
Read 2 more answers
From a bag containing 5 nickels, 8 dimes, and 7 quarters, 5 coins are drawn at random and all at once. What is the probability o
murzikaleks [220]

Answer:

0.13

Step-by-step explanation:

From a bag containing 5 nickels, 8 dimes, and 7 quarters, 5 coins are drawn at random and all at once

we need to select 2 nickels from 5 nickels and select 2 dimes from 8 dimes and 1 quarter from 7 quarters

There are total of 5+8+7=20 coins

select 5 coins from total of 20 coins

2 nickels can be selected from 5 nickels in 5C2 ways

5C2=\frac{5!}{2!(5-2)!} =\frac{5!}{2!(3!)!}=10

2 dimes selected from 8 dimes

8C2=\frac{8!}{2!(8-2)!} =\frac{6!}{2!(6!)}=28

1 quarter selected from 7 quarter

7C1=\frac{7!}{1!(7-1)!} =\frac{7!}{1!(6!)}=7

5 coins selected from 20 coins

20C5=\frac{20!}{5!(15)!} =15504

probability of getting 2 nickels, 2 dimes, and 1 quarter

\frac{10 \cdot 28 \cdot 7}{15504} =\frac{1960}{15504} =0.13

5 0
3 years ago
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