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3 years ago

Find Y ..............

Mathematics

1 answer:

N76 [4]3 years ago

4 0

Answer:

y = 40 / sqrt(pi)

Step-by-step explanation:

The area is 400

We want to find the diameter

400 = pi r^2

Divide each side by pi

400/ pi = r^2

Take the square root of each side

sqrt(400/ pi) = sqrt(r^2)

20/ sqrt(pi) = r

The diameter is twice the radius

2 r = d

2 * 20/ sqrt(pi) = d

40 / sqrt(pi) =d

y is the diameter so

y = 40 / sqrt(pi)

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PART A: Mrs. konsdorf claims that angle R is a right angle.Is Mrs. konsdorf correct? explain your reasoning PART B: if T is trab

Anna007 [38]

Answer:

Part A: Angle R is not a right angle.

Part B; Angle GRT' is a right angle.

Step-by-step explanation:

Part A:

From the given figure it is noticed that the vertices of the triangle are G(-6,5), R(-3,1) and T(2,6).

Slope formula

$m=\frac{y_2-y_1}{x_2-x_1}$

The product of slopes of two perpendicular lines is -1.

Slope of GR is

$\text{Slope of GR}=\frac{1-5}{-3-(-6)}=\frac{-4}{3}$

Slope of RT is

$\text{Slope of RT}=\frac{6-1}{2-(-3)}=\frac{5}{5}=1$

Product of slopes of GR and RT is

$\frac{-4}{3}\times 1=\frac{-4}{3}\neq -1$

Therefore lines GR and RT are not perpendicular to each other and angle R is not a right angle.

Part B:

If vertex T translated by rule

$(x,y)\rightarrow(x-1,y-2)$

Then the coordinates of T' are

$(2,6)\rightarrow(2-1,6-2)$

$(2,6)\rightarrow(1,4)$

Slope of RT' is

$\text{Slope of RT'}=\frac{4-1}{1-(-3)}=\frac{3}{4}$

Product of slopes of GR and RT' is

$\frac{-4}{3}\times \frac{3}{4}=-1$

Since the product of slopes is -1, therefore the lines GR and RT' are perpendicular to each other and angle GRT' is a right angle.

6 0

3 years ago

A, 5+x = 17

Vlad [161]

A. 5+x=17, x = 17-5=12

B. x = 4 x 2.5 = 10

C. x = 27+12 = 39

D. x = 16:4 = 4

E. x = 9 : 3/4 = 12

Answer A and E

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2 years ago

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Butoxors [25]

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Answer:

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Find Y .............. ​

Find Y ..............