A or B cuz you need one of the two to have WiFi cuz my computer asks if i have an adapter and then SSID
Answer:
just repeat the move forward as many times until you get to the hole and fill 1
Explanation:
i think this might work
if it does can i have brainliest
Meaning you are busy and focused at work
Answer:
The method in Java is as follows:
public static int numUnique(int list[]) {
int unique = 1;
for (int i = 1; i < list.length; i++) {
int j = 0;
for (j = 0; j < i; j++) {
if (list[i] == list[j])
break;
}
if (i == j)
unique++;
}
return unique;
}
Explanation:
This line defines the numUnique method
public static int numUnique(int list[]) {
This initializes the number of unique elements to 1
int unique = 1;
This iterates through the list
for (int i = 1; i < list.length; i++) {
The following iteration checks for unique items
int j = 0;
<em> for (j = 0; j < i; j++) {
</em>
<em> if (list[i] == list[j]) </em><em>If current element is unique, break the iteration</em><em>
</em>
<em> break; </em>
<em> }
</em>
if (i == j)
unique++;
}
This returns the number of unique items in the list
return unique;
}
<u>Explanation:</u>
a.
- One user can read the private data of another user-privacy.
- One user can prevent another user from getting anything done-denial of service.
Indeed, in any multiprogramming and time-sharing environment since the computers of users are networked together, then it is very possible for a bad actor to read the private data of another user, or even prevent another user from accessing their computer by employing a denial of service attack on the network. In other words, the network would be unable to handle the request of users since has been overloaded by another user.
b. a. Yes - if we can ensure that the operating system prevents any sharing of data between users, either for reading or writing and fairly shares the computer, then we can achieve the same level of security.