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Tcecarenko [31]
3 years ago
7

Abe ate 1/6 of a small pizza. Aisha ate 1/8 of a small pizza. Who ate more?

Mathematics
1 answer:
Papessa [141]3 years ago
6 0

abe

Step-by-step explanation:

aisha ate more because aisha slice was cut into more pieces. then leaving her with the smallest peice and abe had less slices then leaving him with bigger slices so in conclusion abe ate more

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64 percent rounds to the nearest
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Complete the factoring.<br> 3y+30=3(3)
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3(y+10) = 3(3). For additional simplification, the answer may be written as 
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The Marriott Hotel charges $150 per night for a family
SVETLANKA909090 [29]

Answer:

For two night in the hotel, you would pay $333 (including tax)

Step-by-step explanation:

Without tax, the price for 2 nights would be $150 times 2. So the price without tax would be....

$150 x 2 = $300

But then we have to be aware of 11% tax so we would multiply the price for two nights by 1.11 and get...

$300 x 1.11 = $333

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3 years ago
Read 2 more answers
Are carpet coast $15 per square metre. The total delivery charge is $21 Peter buys N squared metres of carpet what is the expres
postnew [5]

Answer:

15N + 21

Step-by-step explanation:

We are given that,

Amount of carpet bought by Peter = N meter²

The cost per meter square of the carpet = $15

So, the cost of 'N' meter square of carpet = 15N dollars.

Also, the delivery charge for the carpet = $21

Thus, the total cost of the carpet is given by,

Total cost = Cost per square meter + Delivery charge

i.e. Total cost = 15N + 21 (in dollars).

Hence, the expression representing the cost in dollars is '15N + 21'.

8 0
3 years ago
A 15 kilogram object is suspended from the end of a vertically hanging spring stretches the spring 1/3 meters. At time t = 0, th
Yuri [45]

Answer:

15\frac{d^{2}y(t)}{dt^{2} }  - 441.45y(t) = ± 170 cos(5t)

y(0)=0, y'(0)=0

Step-by-step explanation:

See the attached image

This problem involves Newton's 2nd Law which is: ∑F = ma, we have that the acting forces on the mass-spring system are: F_{r} (t) that correspond to the force of resistance on the mass by the action of the spring and F(t) that is an external force with unknown direction (that does not specify in the enounce).

For determinate F_{r} (t) we can use Hooke's Law given by the formula F_{r} (t) = k y(t) where k correspond to the elastic constant of the spring and y(t) correspond to  the relative displacement of the mass-spring system with respect of his rest state.

We know from the problem that an 15 Kg mass stretches the spring 1/3 m so we apply Hooke's law and obtain that...

k = \frac{F_{r}}{y} = \frac{mg}{y} = \frac{15 Kg (9.81 \frac{m}{s^{2} } )}{\frac{1}{3} m}  = 441.45 \frac{N}{m}

Now we apply Newton's 2nd Law and obtaint that...

F_{r} (t) ± F(t) = ma(t)

F_{r} (t) = ky(t) = 441.45y(t)

F(t) = 170 cos(5t)

m = 15 kg

a(t) = \frac{d^{2}y(t)}{dt^{2} }

Finally... 15\frac{d^{2}y(t)}{dt^{2} }  - 441.45y(t) = ± 170 cos(5t)

We know from the problem that there's not initial displacement and initial velocity, so... y(0)=0 and y'(0)=0

Finally the Initial Value Problem that models the situation describe by the problem is

\left \{ 15\frac{d^{2}y(t)}{dt^{2} }  - 441.45y(t) = \frac{+}{} 170 cos(5t) \atop {y(0)=0, y'(0)=0\right.

6 0
3 years ago
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