N = 3 ( the next number is 3 plus the previous number
sequence formula = an = 3(n-1) +2
so for term the term that =59
59 = 3(n-1) +2
distribute:
59 = 3n -3+2
59 = 3n -1
60 = 3n
n = 60/3
n = 20
59 is the 20th term
Answer:
<h3>Graph 3</h3>
Line starting at x = -2
- <u>Domain</u>: x ≥ -2
- <u>Range</u>: y ≥ 0
<h3>Graph 4</h3>
Vertical line
- <u>Domain</u>: x = 3
- <u>Range</u>: y = any real number
<h3>Graph 5</h3>
Quadratic function with negative leading coefficient and max value of 3
- <u>Domain</u>: x = any real number
- <u>Range</u>: y ≤ 3
<h3>Graph 6</h3>
Curve with non-negative domain and min value of -2
- <u>Domain</u>: x ≥ 0
- <u>Range</u>: y ≥ -2
<h3>Graph 7</h3>
Line with no restriction
- <u>Domain</u>: x = any real number
- <u>Range</u>: y = any real number
<h3>Graph 8</h3>
Quadratic function with positive leading coefficient and min value of 4
- <u>Domain</u>: x = any real number
- <u>Range</u>: y ≥ 4
<h3>Graph 9</h3>
Parabola with restriction at x = -4
- <u>Domain</u>: x = any real number except -4
- <u>Range</u>: y = any real number
<h3>Graph 10</h3>
Square root function with star point (2, 0)
- <u>Domain</u>: x ≥ 2
- <u>Range</u>: y ≥ 0
Answer: These Lines are <em>Parallel</em>
Step-by-step explanation: For two lines to be parallel, they must have the same slope with different y-intercepts. Both of the lines above have a slope of 3 and differing y-intercepts of 4 and -5. Therefore, these lines must be parallel to one another.
2/3 ÷ 4
2/3 ÷ 4/1
We invert the 4/1 to 1/4 and multiply out.
2/3 × 1/4
= 1/3 × 1/2 2 into 4 is 2.
= 1/(3 × 2)
= 1/6
Hope this helps.
B earns 11/20 of the profit.
(20-9)/20 = 11/20.
If the actual value is needed. You could do it one of two ways.
1---> 29000*11/20 = 15,950
2---> 29000*9/20 = 13,050
29,000 - 13,050 = 15,950
