Using proportions, the algebraic expression for the cost of the 24 ads with the discount is:
Cost = 21.12c.
In which c is the cost of a single add.
<h3>What is a proportion?</h3>
A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.
For this problem, if more than 10 ads are posted, the cost C of each job is discounted by 12%, that is, it is of 88% of C. Hence, the algebraic expression for the cost of the 24 ads with the discount is:
C = 24 x 0.88 x c = 21.12c
In which c is the cost of a single add.
More can be learned about proportions at brainly.com/question/24372153
#SPJ1
Answer: choice A) -4
-----------------------------------------------
Step 1) Draw a vertical line through 1 on the x axis
Step 2) Mark the point where the vertical line and the blue curve intersect (or cross each other)
Step 3) Draw a horizontal line through the point marked in step 2. Note how this horizontal line goes through -4 on the y axis.
So the point (1,-4) is on the blue curve. This means if x = 1 is the input then y = -4 is the output. Recall that y = f(x). So f(x) = -4 is the output as well when the input is x = 1.
In short, this is why f(1) = -4
Me Hamilton gave 210 coupons two days is throw you off because total was 24 so 14 times 15
Step-by-step answer:
Referring to the attached diagram, the resultant of two forces each with magnitude F and inclined to each other at 2a equals
Ra = 2Fcos(a) ..............................(1)
Similarly, the resultant of two forces each with magnitude F and inclined to each other at 2b equals
Rb = 2Fcos(b)..............................(2)
We are given that
Ra = 2Rb ....................................(3)
Substitute (1) & (2) in (3) gives
2Fcos(a) = 2(2Fcos(b))
Expand
2Fcos(a) = 4Fcos(b)
Simplify
cos(a) = 2 cos(b) QED
Note: Please note that you might have a faster response if you posted this question in the physics or the (new) Engineering section.
Have a nice day!