Explanation:
Effective communication with patients will enable one to know the needs of the patient better as well as reducing the barriers to understanding each other for both parties.
To be an effective communicator while educating patients, the person must:
- It is important to establish good rapport with the patient. By so doing they can trust you and let you in. Show empathy. Do not make them feel like you are judging them
- Use proper body language. Make eye contacts and try to be on the same level as the patient so you can be face to face with them.
- make the interaction easier for them. You have to keep questions as well as your sentences short and moderate. Stay on topic and always make sure that concepts are clear to them.
- show respect. try not to speak with commands. Give the patient opportunity to make choices.
- be patient with them. Due to age or the nature of their illnesses, the patient may be slow in speech or movement. help them to move at their own pace by not rushing them.
- give them time to respond and ask questions. this will make communication more effective.
- you cause graphics where necessary or written instructions for the patient.
Answer:
186 N
ExplanatioN
Weight is essentially just a measurement of the force of gravity, so you can use this equation.
F = mg
Force = Mass × Acceleration due to Gravity
F = 19kg × 9.8m/s^2. (Acceleration due to Gravity on Earth.)
F = 186.02N
Answer:
At the dimer-dimer interface there might be acting non-covalent forces (van der waals, Hidrogene bridges, hydrophobic forces)
At the monomer-monomer interface there might be covalent forces acting (disulfide bridges).
Explanation:
On the SDS-PAGE application works by disrupting non-covalent bonds in the proteins, and so denaturing them. Therefore, the disulfide bridges won´t be disrupted, so the monomers will remain bounded.
The next step to take is to used the scientific method to explore the observations she has made in order to discover the facts behind her observations. She should ask questions about the hotness of the pavement and form an hypothesis to support her observation. She should then set up an appropriate experiment to confirm her hypothesis. After the conduction of the experiment, she should analyze her results and then draw a conclusion.<span />
Answer:
38.7 units
Explanation:
a = 3.00 t² – 4.20 t
Integrate to find velocity as a function of time.
v = ∫ a dt
v = ∫ (3.00 t² – 4.20 t) dt
v = 1.00 t³ – 2.10 t² + C
The object starts at rest, so at t = 0, v = 0.
0 = 1.00 (0)³ – 2.10 (0)² + C
0 = C
v = 1.00 t³ – 2.10 t²
Integrate to get position as a function of time.
x = ∫ v dt
x = ∫ (1.00 t³ – 2.10 t²) dt
x = 0.250 t⁴ – 0.700 t³ + C
Find the difference in positions between t = 4.50 and t = 0.
Δx = [0.250 (4.50)⁴ – 0.700 (4.50)³ + C] – [0.250 (0)⁴ – 0.700 (0)³ + C]
Δx = 0.250 (4.50)⁴ – 0.700 (4.50)³
Δx = 38.7
The object moves 38.7 units.
