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notka56 [123]
3 years ago
11

How much current will a 500 W vacuum cleaner draw if it has a resistance of 30Ω?

Physics
1 answer:
Strike441 [17]3 years ago
3 0

Answer:

Electric current, I = 4.08 A    

Explanation:

We have,

Power of vacuum cleaner is 500 W

Resistance of vacuum cleaner is 30 ohms

It is required to find the current flowing through the vacuum cleaner. It can be calculated using the definition of power delivered. Its formula is given by :

P=I^2R

I is electric current

I=\sqrt{\dfrac{P}{R}} \\\\I=\sqrt{\dfrac{500}{30}} \\\\I=4.08\ A

So, the electric current flowing through the vacuum cleaner is 4.08 A.

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In which of the following does enstein's famous equation apply?
Delicious77 [7]

Answer:

D

Explanation:

7 0
3 years ago
Both gamma rays and x-rays are used to see inside the body. True or False
lozanna [386]

Answer:

True

Explanation:

Gamma rays and X-rays are made of packets of energy (photons) without mass or charge, with high penetrating power such that they can pass through the human body and impinge on a photographic plate creating an image of the interior of the human body. They electromagnetic radiation of high energy and high frequency that emanate from some natural sources such as cosmic sun rays and radon gas.

Gamma rays and X-rays can be man made by use of man made electronic devices and radioactive elements

Gamma rays and X-rays find use in airport security scanning and imaging services for medical testing.

8 0
3 years ago
A ball is kicked at 30.0 m/s at an angle of 20.0°. Beneath the tilted columns calculate the vertical and horizontal components.
RSB [31]

The velocities at time <em>t</em> are

• Horizontal:

<em>v</em> = (30.0 m/s) cos(20.0º)

• Vertical:

<em>v</em> = (30.0 m/s) sin(20.0º) - <em>g</em> <em>t</em>

(where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity)

If you only want the <u>initial</u> velocities, they are

• Horizontal:

<em>v</em> = (30.0 m/s) cos(20.0º) ≈ 28.2 m/s

• Vertical:

<em>v</em> = (30.0 m/s) sin(20.0º) ≈ 10.3 m/s

(just set <em>t</em> = 0)

As far as starting equations go, you can derive everything from the definition for average acceleration:

<em>a</em> = ∆<em>v</em> / ∆<em>t</em> = (final <em>v</em> - initial <em>v</em>) / <em>t</em>

→   <em>v</em> = <em>u</em> + <em>a</em> <em>t</em>

(here, <em>u</em> stands in for "initial <em>v</em>" and <em>v</em> is simply velocity at time <em>t</em> )

There is no acceleration in the horizontal direction, while the ball is essentially in free-fall in the vertical direction.

6 0
3 years ago
You've been called in to investigate a car accident by the Bluffs. A car went over a 7.93 meter high cliff
valina [46]

Explanation:

Use the height of the cliff to determine how long it took the car to land.

Take down to be positive.  Given:

Δy = 7.93 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

7.93 m = (0 m/s) t + ½ (9.8 m/s²) t²

t = 1.27 s

Use the time to calculate the horizontal velocity.

Given:

Δx = 26.7 m

a = 0 m/s²

Find: v₀

Δx = v₀ t + ½ at²

26.7 m = v₀ (1.27 s) + ½ (0 m/s²) (1.27 s)²

v₀ = 21.0 m/s

The driver was going 21.0 m/s, faster than the speed limit of 9.72 m/s.

4 0
4 years ago
Read 2 more answers
A spherical helium filled balloon (B) with a hanging passenger cage being held by a single vertical cable (C) attached to Earth
Gre4nikov [31]

Answer:

The tension is  T  = 4326.7 \  N

Explanation:

From the question we are told that

   The  total mass is  m  =  200 \  kg

    The  radius is r = 5 \  m

     The  density of air is  \rho_a  =  1.225 \ kg/m^3

Generally the upward  force acting on the balloon is mathematically represented as

        F_N  =   T  + mg

=>     (\rho_a  *  V  *  g ) =   T  + mg

=>   T  =  (\rho_a  * V  *  g   )  - mg

Here V is the volume  of the spherical helium filled balloon which is mathematically represented as

      V  =  \frac{4}{3}  * \pi r^3

=>   V  =  \frac{4}{3}  * 3.142 *(5)^3

=>   V  = 523.67\  m^3

So

    T  = (1.225 *  523.67*  9.8 ) -  200 *  9.8

   T  = 4326.7 \  N

5 0
3 years ago
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