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2 years ago

How much current will a 500 W vacuum cleaner draw if it has a resistance of 30Ω?

Physics

1 answer:

Strike441 [17]2 years ago

3 0

Answer:

Electric current, I = 4.08 A

Explanation:

We have,

Power of vacuum cleaner is 500 W

Resistance of vacuum cleaner is 30 ohms

It is required to find the current flowing through the vacuum cleaner. It can be calculated using the definition of power delivered. Its formula is given by :

$P=I^2R$

I is electric current

$I=\sqrt{\dfrac{P}{R}} \\\\I=\sqrt{\dfrac{500}{30}} \\\\I=4.08\ A$

So, the electric current flowing through the vacuum cleaner is 4.08 A.

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We use a battery to cause a continuous potential difference by getting charges to separate. Explain why the terminals of a batte

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Answer:

To create an electric potential difference between the ends of the conductor.

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How much heat is needed to vaporize 10.00 grams of water at 100.0°C? The latent heat of vaporization of water is 2,259 J/g

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Answer:

Heat of vaporization will be 22.59 j

Explanation:

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2 years ago

Read 2 more answers

The density of mobile electrons in copper metal is 8.4 1028 m-3. Suppose that i = 4.6 1018 electrons/s are drifting through a co

Vesna [10]

Answer:

The time is 106.7 minute.

Explanation:

Given that,

Density $= 8.4\times10^{28}\ m^3$

Current $i = 4.6\times10^{18}\ electron/s$

Diameter of wire = 1.2 mm

Length = 31 cm

We need to calculate the drift velocity

Using formula of drift velocity

$v_{d}=\dfrac{I}{neA}$

$v_{d}=\dfrac{Ne}{tne\times\pi r^2}$

Put the value into the formula

$v_{d}=\dfrac{4.6\times10^{18}}{8.4\times10^{28}\times\pi\times(0.6\times10^{-3})^2}$

$v_{d}=4.842\times10^{-5}\ m/s$

We need to calculate the time

Using formula for time

$v_{d}=\dfrac{l}{t}$

$t=\dfrac{l}{v_{d}}$

Where, l = length

$v_{d}$ = drift velocity

Put the value into the formula

$t=\dfrac{31\times10^{-2}}{4.842\times10^{-5}}$

$t=6402.31\ sec$

$t=106.7\ minute$

Hence, The time is 106.7 minute.

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3 years ago

The properties of element 17 are most similar to which of the following elements?

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