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Nutka1998 [239]
3 years ago
13

In doing a load of clothes, a clothes dryer uses 16 A of current at 240 V for 45 min. A personal computer, in contrast, uses 2.7

A of current at 120 V. With the energy used by the clothes dryer, how long (in hours) could you use this computer to "surf" the internet?
Physics
1 answer:
jasenka [17]3 years ago
6 0

Explanation:

Given that,

Current of clothes dryer, I = 16 A

Voltage, V = 240 V

Time, t = 45 min = 2700 s

Current of personal computer, I' = 2.7 A

Voltage, V' = 120 C

Energy used by clothes dryer is given by :

E=I^2Rt\\\\E=IVt\\\\E=16\times 240\times 2700\\E=1.03\times 10^7\ J

Let t' is the time for this computer to "surf" the internet. Again using formula of energy used as :

E=I'V't'\\\\t'=\dfrac{E}{I'V'}\\\\t'=\dfrac{1.03\times 10^7}{2.7\times 120}\\\\t'=31790.12\ s\\\\t'=8.83\ h

So, for 8.83 hours you could use this computer to "surf" the internet.

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A driver in a 2290-kg car car traveling at 42.7 m/s slams on the brakes and skids to a stop. If the coefficient of friction betw
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Answer:

126.56 m

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Applying,

-F = ma............. Equation 1

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F = mgμ.......... Equation 2

Where g = acceleration due to gravity, μ = coefficient of friction

Substitute equation 2 in equation 1

-mgμ = ma

a = -gμ.............. Equation 3

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a = -9.8×0.735

a = -7.203 m/s²

Finally,

Applying

v² = u²+2as.............. Equation 4

Where v = final velocity, u = initial velocity, s = distance

From the question,

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Substitute these values into equation 4

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3 years ago
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