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balu736 [363]
3 years ago
7

Cloe, Dixie Doll treasurer, deposits the club’s receipts. She has 4 checks for $10.00 each, 12 for $7.50, and cash consisting of

six 20-dollar bills, five 10-dollar bills, and 18 one-dollar bills. What is the total deposit?
Mathematics
1 answer:
wel3 years ago
5 0
$318 deposit

4x10=40
12x7.50=90
6x20=120
5x10=50
18x1=18

40+90+120+50+18=$318.00 deposit
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6 times 7 to the second power
Travka [436]
Hello!

To solve this question, we must first add the exponent into the number 7 before multiplying it by the number 6. 

7 to the second power simply means 7x7. 

7x7= 49

Now that the exponent is in the equation, we can multiply 49 by 6 to find your final answer. 

6 x 49 = 294

I hope this helps answer your question! Have a great day!
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3 years ago
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Pls help me with 4 , 5 , and 6 and show me how you did it i will mark brainlist !!
LuckyWell [14K]

Answer:

2 on top and bottom of 4   5 is 3 on top and bottom      and lastly 6 is 8 on top and bottom.

Step-by-step explanation:

all you have to do is divide the two bottom numbers on each problem and the answer to the problem will be the same on top and bottom

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4 years ago
What is the volume of a square pyramid if the perimeter of the base is 44 in and the height is 19 in.? Round to the nearest tent
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Step-by-step explanation:

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3 years ago
A certain firm has plants A, B, and C producing respectively 35%, 15%, and 50% of the total output. The probabilities of a non-d
Sliva [168]

Answer:

There is a 44.12% probability that the defective product came from C.

Step-by-step explanation:

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

-In your problem, we have:

P(A) is the probability of the customer receiving a defective product. For this probability, we have:

P(A) = P_{1} + P_{2} + P_{3}

In which P_{1} is the probability that the defective product was chosen from plant A(we have to consider the probability of plant A being chosen). So:

P_{1} = 0.35*0.25 = 0.0875

P_{2} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{2} = 0.15*0.05 = 0.0075

P_{3} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

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P(B) is the probability the product chosen being C, that is 50% = 0.5.

P(A/B) is the probability of the product being defective, knowing that the plant chosen was C. So P(A/B) = 0.15.

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P = \frac{0.5*0.15}{0.17} = 0.4412

There is a 44.12% probability that the defective product came from C.

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