STEP BY STEP PLS

1 answer:

4 0

C ( To make things simple, let's turn 80% into a fraction, 8/10. To get a common denominator let's turn 8/10 into 4/5. Since they are both of equal size, the first group would have 2/5 left-handed people and the second 1/5 left-handed people. Let's imagine that each group has 5 people in it. There would be 10 people in total. There is 1 person for each fifth so we can add now. 4 + 3 = 7 right handed people. To check, 2 + 1 = 3 and 3 + 7 = 10. so 7/10 of the class is right-handed. )

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Identify the leading coefficient in the following polynomial:<br> – 5x² + 3x - 7

insens350 [35]

Answer:

-5

Step-by-step explanation:

The leading coefficient means the thing you're multiplying your highest power by. Here, your highest power of x is x^2, and that term's coeff. is -5, so the leading coefficient is -5.

7 0

2 years ago

Suppose ten students in a class are to be grouped into teams. (a) If each team has two students, how many ways are there to form

ValentinkaMS [17]

Answer:

(a) There are 113,400 ways

(b) There are 138,600 ways

Step-by-step explanation:

The number of ways to from k groups of n1, n2, ... and nk elements from a group of n elements is calculated using the following equation:

$\frac{n!}{n1!*n2!*...*nk!}$

Where n is equal to:

n=n1+n2+...+nk

If each team has two students, we can form 5 groups with 2 students each one. Then, k is equal to 5, n is equal to 10 and n1, n2, n3, n4 and n5 are equal to 2. So the number of ways to form teams are:

$\frac{10!}{2!*2!*2!*2!*2!}=113,400$

For part b, we can form 5 groups with 2 students or 2 groups with 2 students and 2 groups with 3 students. We already know that for the first case there are 113,400 ways to form group, so we need to calculate the number of ways for the second case as:

Replacing k by 4, n by 10, n1 and n2 by 2 and n3 and n4 by 3, we get:

$\frac{10!}{2!*2!*3!*3!}=25,200$