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Blababa [14]
4 years ago
7

A rectangular box is constructed in 3-space with one corner at the origin and other vertices at (1, 0, 0), (0, 4, 0), (0, 0, 2).

Find the length of the diagonal of the box.
Mathematics
1 answer:
77julia77 [94]4 years ago
7 0

The space diagonal will have length ...

... d = √(1² +4² +2²) = √(1 +16 +4) = √21

_____

This can be found using the Pythagorean theorem. A drawing can help. Find the length of any face diagonal, then use that length as the leg of a right triangle whose hypotenuse is the space diagonal and whose other leg is the edge length not used in the first calculation.

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20 1/3 + x = -9 round your answer to the nearest hundredth
nadya68 [22]

Answer:

I would think it's X= -29 1/3

Step-by-step explanation:

You have 20 1/3 already, and to get to a negative when you have a positive number, to the positive you would need to add a larger negative. (If that makes any sense, it's hard to explain.) So you have to get rid of the 20 1/3 and you have to get to -9, so I would add a 9 to 20 1/3 to get 29 1/3, and make that number negative because then it will cancel the positive out. Making it -9.

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3 years ago
Please answer quick!
elena-s [515]

Answer:

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Step-by-step explanation:

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6 0
4 years ago
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Vadim26 [7]

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Step-by-step explanation:

6 0
3 years ago
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What are two possible measures of the angle below?
deff fn [24]

For this case what we must do is take into account that the angle can be measured in two ways starting from the positive x axis.

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Answer

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