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Blababa [14]
3 years ago
7

A rectangular box is constructed in 3-space with one corner at the origin and other vertices at (1, 0, 0), (0, 4, 0), (0, 0, 2).

Find the length of the diagonal of the box.
Mathematics
1 answer:
77julia77 [94]3 years ago
7 0

The space diagonal will have length ...

... d = √(1² +4² +2²) = √(1 +16 +4) = √21

_____

This can be found using the Pythagorean theorem. A drawing can help. Find the length of any face diagonal, then use that length as the leg of a right triangle whose hypotenuse is the space diagonal and whose other leg is the edge length not used in the first calculation.

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Answer:

X+y=180, Y=Z, X+Z=180

Step-by-step explanation:

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What is the square root of 789?
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Which of the following rational functions is graphed below?​
asambeis [7]

Answer:

B.

Step-by-step explanation:

According to the graph the function is defined for all real number except -3 and 7 (where the two red dashed vertical lines cross the x-axis)

so our function should be :

\frac{1}{(x-(-3))(x-7)} =\frac{1}{(x+3)(x-7)}

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2 years ago
Finding a polynomial of a given degree with given zeros
galben [10]

Since f(x) is a polynomial with 3rd degree, then it will have 3 roots (zeroes)

One of them is real and the other two are complex conjugate roots

Since the real root is 4, then

x = 4

Since the complex root is (1 - i), then

The other root will be the conjugate of it (1 + i)

x = (1 - i)

x = (1 + i)

To find f(x) we will multiply the three factors of it

We can get the factors from the zeroes

x=4

Subtract 4 from both sides

\begin{gathered} x-4=4-4 \\ x-4=0 \end{gathered}

The first factor is (x - 4)

\begin{gathered} x=1-i \\ x-(1-i)=(1-i)-(1-i) \\ x-1+i=0 \end{gathered}

The second factor is (x - 1 + i)

The third factor is (x - 1 - i)

f(x)=(x-4)(x-1+i)(x-1-i)

We will multiply them to find f(x)

\begin{gathered} (x-1+i)(x-1-i)= \\ x^2-x-ix-x+1+i+ix-i-(i^2)= \\ x^2-2x+1-(-1)= \\ x^2-2x+1+1= \\ x^2-2x+2 \end{gathered}

Multiply it by (x - 4)

\begin{gathered} f(x)=(x-4)(x^2-2x+2) \\ f(x)=x^3-2x^2+2x-4x^2+8x-8 \\ f(x)=x^3-6x^2+10x-8 \end{gathered}

The answer is

f(x)=x^3-6x^2+10x-8

5 0
1 year ago
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