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yKpoI14uk [10]
3 years ago
5

Reset All

Physics
1 answer:
Ierofanga [76]3 years ago
7 0

Answer:

B)The push exerted by the ball on the grounds.

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A car is traveling at 114 m/s and changes its velocity to 77 m/s in 9 sec.
suter [353]

Answer:

<u>Given</u><u> </u><u>-</u>

  • Initial Velocity, u = 114 m/s
  • Final velocity, v = 77 m/s.
  • Time taken, t = 9 sec.

<u>To</u><u> </u><u>find</u><u> </u><u>-</u><u> </u>

  • Acceleration of the car.

<u>Solu</u><u>tion</u><u> </u><u>-</u>

Here, using the equation of motion v = u + at we can find the acceleration easily.

★ Here,

  1. V = Final velocity
  2. U = Initial Velocity
  3. A = Acceleration
  4. T = Time.

<u>Subs</u><u>tituting</u><u> </u><u>the</u><u> </u><u>values</u><u> </u><u>-</u>

→ 77 = 114 + a(9)

→ 9a = 114 - 77

→ 9a = 37

→ a = 37/9

→ a = 4.1 m/s

<u>There</u><u>fore</u><u>,</u><u> </u><u>the</u><u> </u><u>accele</u><u>ration</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>car</u><u> </u><u>will</u><u> </u><u>be</u><u> </u><u>4</u><u>.</u><u>1</u><u> </u><u>m</u><u>/</u><u>s</u><u>.</u>

5 0
3 years ago
ASAP HELP!!
rodikova [14]
The force of gravity between two objects is increased when the mass of objects is increased.
3 0
4 years ago
Read 2 more answers
15) A 328-kg car moving at 19.1 m/s in the +x direction hits from behind a second car moving at 13 m/s in the same direction. If
kolbaska11 [484]

Answer:

Explanation:

Given that,

Mass of first car

M1= 328kg

The car is moving in positive direction of x axis with velocity

U1 = 19.1m/s

Velocity of second car

U2 = 13m/s, in the same direction as the first car..

Mass of second car

M2 = 790kg

Velocity of second car after collision

V2 = 15.1 m/s

Velocity of first car after collision

V1 =?

This is an elastic collision,

And using the conservation of momentum principle

Momentum before collision is equal to momentum after collision

P(before) = P(after)

M1•U1 + M2•U2 = M1•V1 + M2•V2

328 × 19.1 + 790 × 13 = 328 × V1 + 790 × 15.1

16534.8 = 328•V1 + 11929

328•V1 = 16534.8—11929

328•V1 = 4605.8

V1 = 4605.8/328

V1 = 14.04 m/s

The velocity of the first car after collision is 14.04 m/s

5 0
3 years ago
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