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4 years ago

ASAP HELP!!

Physics

2 answers:

ehidna [41]4 years ago

6 0

Answer:

C- The gravitational force between the object decreases.

Explanation:

Explanation

Gravity is the force of attraction between all masses in the universe.

The magnitude of a gravitational force depends on

the masses of the objects

the distance between the objects

The gravitational force between two bodies decreases as their masses decrease.

rodikova [14]4 years ago

3 0

The force of gravity between two objects is increased when the mass of objects is increased.

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Jack and Jill are maneuvering a 3300 kg boat near a dock. Initially the boat's position is < 2, 0, 3 > m and its speed is

Paraphin [41]

Answer:

The workdone by Jack is $W_{jack} = -1050J$

The workdone by Jill is $W_{Jill} = 0J$

The final velocity is $v = 1.36 m/s$

Explanation:

From the question we are given that

The mass of the boat is $m_b = 3300kg$

The initial position of the boat is $P_i = (2 \r i + 0 \r j + 3\r k)m$

The Final position of the boat is $P_f = (4\r i + 0 \r j + 2\r k )\ m$

The Force exerted by Jack $\r F = (-420\r i + 0 \r j + 210\r k) \ N$

The Force exerted by Jill $\r F_{Jill} =(180 \r i + 0\r j + 360\r k)$

Now to obtain the displacement made we are to subtract the final position from the initial position

$\r P = P_f - P_i$

$= (4\r i + 0\r j + 2 \r k) - (2\r i + 0\r j + 3\r k )$

$= (2\r i + 0\r j -\r k )m$

Now that we have obtained the displacement we can obtain the Workdone

which is mathematically represented as

$W =\r F * \r P$

The amount of workdone by jack would be

$W_{jack} =\r F * \r P$

$= [(-420\r i +0\r j +210\r k)(2\r i + 0\r j - \r k)]$

$= (-420) (2) + (210)(-1)$

$= -840 - 210$

$=-1050J$

The amount of workdone by Jill would be

$W_{Jill} =\r F * \r P$

$= [(180 \r i + 0\r j + 360\r k)(2\r i +0\r j -\r k)]$

$= (180 )(2) +(360)(-1)$

$=0J$

According to work energy theorem the Workdone is equal to the kinetic energy of the boat

$W = K.E = \frac{1}{2} m *[v^2 - (1.1)^2]$

$-1050 = 0.5*3300 [*v^2- (1.1)^2]$

$-1050 = 1650 [v^2 -1.21]$

$0.6363 = v^2 -1.21$

$v^2 = 0.6363+1.21$

$v^2 =1.846$

$v = 1.36\ m/s$

6 0

4 years ago

Which is an example of a chemical change?

Deffense [45]

Burning a log of wood is an example of a chemical change

5 0

3 years ago

You are designing a new piece of fishing equipment that will allow you to catch a fish from the surface. You know that water ref

OleMash [197]

Answer:

Law of refraction

Explanation:

An experiment to analyze the refraction of light in water can easily be performed with a laser pointer and protractor.

We throw the fishing rod line into the water, place the protractor at the point where the line touches the water and use the direction of the line for the direction of the laser pointer (on), the laser is visible by the reflection on the particles in the air.

The vertical line is called Normal and all angles must be measured with respect to this reference in optics.

Having these angles and the refractive index of water we can use the law of refraction

n₁ sin θ₁ = n₂ sin θ₂

θ₂ = $sin^{-1} ( \frac{n_1}{n_2} \ sin \ \theta_1 )$

we can repeat several times to analyze several different input points (different angles) and to decrease the errors in the measurements.

the refractive index of air is n1 = 1 and n2= 1.33 (water)

4 0

3 years ago

What is the maximum frequency a human eardrum is able to perceive?

cestrela7 [59]

Maximum generally is 20kHz
beyond 20kHz is considered ultrasound which we cant hear

7 0

4 years ago

A solid cylinder (1 =1/2mr2 ) with a mass of 4.83 kg and a radius of 0.057 m starts

netineya [11]

Answer:

v = 7.32 m/s

Explanation:

The potential energy will convert to kinetic energy

½Iω² + ½mv² = mgh

Iω² + mv² = 2mgh

(½mR²)(v/R)² + mv² = 2mgh

½mv² + mv² = 2mgh

½v² + v² = 2gh

3v²/2 = 2gh

v² = 4gh/3

v² = 4(9.81)(4.10)/3

v² = 53.628

v = 7.323114...

v = 7.32 m/s

3 0

3 years ago