Answer:
Speed of the aircraft = 36.64 m/s
Explanation:
Consider the vertical motion of the projectile,
We have equation of motion s = ut+0.5at²
Let the velocity of plane be v.
Vertical velocity = vsin55 = Initial velocity of projectile in vertical direction = u
acceleration, a = 9.81 m/s²
displacement , s = 554 m
time, t = 8 s
Substituting,
554 = vsin55 x 8 +0.5 x 9.81 x 8²
v = 36.64 m/s
Speed of the aircraft = 36.64 m/s
Answer:
10 J.
Explanation:
Given that,
Net force acting on the rake, F = 2 N
Distance moved by the rake, d = 5 m
We need to find the kinetic energy gained by the rake. We know that,
Kinetic energy = work done
So,
K = F×d
K = 2 N × 5 m
K = 10 J
So, 10 J of kinetic energy is gained by the rake.
