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N76 [4]
3 years ago
8

The choir is selling candy bars to raise money for a trip they sell each candy bar for $5 there are 7 candy bars in each box and

each student in the choir can sell 2 boxes of candy bars per day there are 5 students in the choir how much money can the choir raise in 8 days?
Mathematics
1 answer:
Reika [66]3 years ago
8 0

Answer:$2800

Step-by-step explanation: Lets first figure out how much money a box of candy bars is worth. We know that each candy bar is worth $5 and that there are 7 candy bars per box. We can multiply 7*5 to figure out that each box is worth $35.

Now lets figure out how many boxes can be sold each day. Each student can sell two boxes a day. 5 students selling 2 boxes each is 5*2= 10 boxes total sold a day.

Now finally we use what we found to figure out the amount of money made per day. We know that there are 10 boxes being sold and that each box makes them $35. We just multiply 10 boxes by $35 to get $350 dollars each day.

Since they sell for 8 days we just multiply 8*$350 to get $2800.

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Answer:

č= 67°

Step-by-step explanation:

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x + 113=180

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2 years ago
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Answer:

The maximum variance is 250.

Step-by-step explanation:

Consider the provided function.

V(x)=1000x(1-x)

V(x)=1000x-1000x^2

Differentiate the above function as shown:

V'(x)=1000-2000x

The double derivative of the provided function is:

V''(x)=-2000

To find maximum variance set first derivative equal to 0.

1000-2000x=0

x=\frac{1}{2}

The double derivative of the function at x=\frac{1}{2} is less than 0.

Therefore, x=\frac{1}{2} is a point of maximum.

Thus the maximum variance is:

V(x)=1000(\frac{1}{2})-1000{\frac{1}{2}}^2

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Hence, the maximum variance is 250.

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3 years ago
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Step-by-step explanation:

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snow_tiger [21]

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2x^2-4xy+xy-2y^2-(2x^2-xy+4xy-2y^2)

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