A function of the form f(x) = abx is modified so that the b value remains the same but the a value is increased by 2. How do the
2 answers:
Answer:
The range stays the same.
The domain stays the same.
Step-by-step explanation:
The function is an exponential function, where <em>a</em> is the coefficient, <em>b</em> is the base and <em>x</em> is the exponent.
The domain for this kind of functions is: All real numbers.
And the range is: (0,∞); this happen because the exponential functions are always positive when <em>a</em>>0.
Therefore, if the value of <em>a</em> is increased by 2, the domains will stay the same and the range will stay the same: (0,∞). The coefficient does not change the domain or the range if it keeps the same sign.
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The average value of over [-1, 3] is
Answer:
The correct option is;
D. x = -1.38 and 0.82
Please find attached the combined function chart
Step-by-step explanation:
The given equation is x³ + 3 = -x⁴ + 4
Plotting the equation using Excel, we have;
f(x) = x³ + 3, h(x) = -x⁴ + 4
x f(x) h(x)
-1.4 0.256 0.1584
-1.39 0.314381 0.26699
-1.38 0.371928 0.373261
-1.37 0.428647 0.477246
-1.36 0.484544 0.57898
Which shows an intersection at the point around -1.38
x f(x) h(x)
0.77 3.456533 3.64847
0.78 3.474552 3.629849
0.79 3.493039 3.610499
0.8 3.512 3.5904
0.81 3.531441 3.569533
0.82 3.551368 3.547878
0.83 3.571787 3.525417
Which shows the intersection point around 0.82
Therefore, the correct option is x = -1.38 and 0.82
From the graphing calculator the intersection point is given as
x = -1.3802775691 and 0.81917251339.
