Let the larger number be w and the smaller number be k;
5w-11=3k
3k+16=4w
Reorganizing the equations;
5w-3k=11
4w-3k=16
Subtracting equation 2 from equation 1:
w=-5
Replacing value of w in equation 1;
5(-5)-11=3k
-25-11=3k
3k=-36
k=-12
The numbers are -5 and -12
the 3rd one. hope this helps
Answer:
1/6
Step-by-step explanation:
Answer:
14, 48, 50
Step-by-step explanation:
To check which set of side length can be used to form a right triangle we use pythagorean theorem
c^2 = a^2 + b^2
biggest side (hypotenuse is c^2)
(a) 14, 48, 50

2500= 196+2304
2500= 2500 that is true
(b) 30, 40, 60

3600= 900+ 1600
3600= 2500 that is false
(c) 14, 50, 60

3600= 196+2500
2500= 2196 that is false
(d) 10, 24,28

784=100+576
784=676 that is false