Find the equation of the line passing through the points A (2,1) B (7,9)
1 answer:
y - y₁ = m(x - x₁)
y - 1 = 1³/₅(x - 2) Point - Slope Form
y - 1 = 1³/₅(x) - 1³/₅(2)
y - 1 = 1³/₅x - 3¹/₅
+ 1 + 1
y = 1³/₅x - 2¹/₅ Slope - Intercept Form
-1³/₅x - y = 1³/₅x - 1³/₅x - 2¹/₅
-1³/₅x - y = -2¹/₅
-1(-1³/₅x - y) = -1(-2¹/₅)
-1(-1³/₅x) + 1(y) = 2¹/₅
1³/₅x - y = 2¹/₅ Standard Form
1³/₅(0) - y = 2¹/₅
0 - y = 2¹/₅
-y = 2¹/₅
-1 -1
y = -2¹/₅ Y - Intercept
(x, y) = (0, -2¹/₅)
You might be interested in
Solution :
Let be the unit vector in the direction parallel to the plane and let
be the component of F in the direction of
and
be the component normal to
.
Since,
Therefore,
From figure,
We know that the direction of is opposite of the direction of
, so we have
The unit vector in the direction normal to the plane, has components :
Therefore,
From figure,
∴
Therefore,
