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Mathematics

1 answer:

stich3 [128]2 years ago

7 0

Answer:

x3=y

Step-by-step explanation:

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FIND THE SUM: (6x^2-2x-3)+(x^2-3x+1) 1.6x^2+6x+3 2.7x^2+5x+2 3.7x^2-5x-2

Butoxors [25]

8x^2-5x-2

method

open bracket

6x^2-2x-3+x^2-3x+1

collect like terms

6x^2+2x^2-3-3x+1

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8x^2-2x-3x-3+1

8x^2-5x-3+1. (-×-=+ addition but keeping sign minus

8x-5x-2. (-×+=-)

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The value of y is directly proportional to the value of x.

Paladinen [302]

Answer:

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Step-by-step explanation:

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2 years ago

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Write the standard form of the line that passes through (-1,-3) and (2,1).

kobusy [5.1K]

Answer:

Step-by-step explanation:

$\mathrm{Line\:passing\:through\:}\left(-1,\:-3\right)\mathrm{,\:}\left(2,\:1\right)\\\\\mathrm{Find\:the\:line\:}\\\mathbf{y=mx+b}\mathrm{\:passing\:through\:}\left(-1,\:-3\right)\mathrm{,\:}\left(2,\:1\right)\\\\\mathrm{Compute\:the\:slope\:}\left(-1,\:-3\right),\:\left(2,\:1\right):\quad \\m=\frac{4}{3}\\\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\\\\\left(x_1,\:y_1\right)=\left(-1,\:-3\right),\:\left(x_2,\:y_2\right)\\\left\\$

$\\m=\frac{1-\left(-3\right)}{2-\left(-1\right)}\\\\Refine\\\\m=\frac{4}{3}\\\\\mathrm{Compute\:the\:}y\mathrm{\:intercept}:\quad b=-\frac{5}{3}\\\\y=\frac{4}{3}x-\frac{5}{3}\\$

Convert equation to standard form

$y - \frac{4}{3} x + \frac{5}{3} = 0\\\\Multiply \:through\: by\: 3;\\\\3\times (y - \frac{4}{3} x + \frac{5}{3} )=0\\\\3y -4x+5 = 0\\Arrange\:n\:form\:of \:;\\Ax +By = C\\\\-4x +3y =-5$